Aufgaben:Exercise 1.4: AMI and MMS43 Code - Revision history

Guenter at 15:54, 24 October 2022

2022-10-24T15:54:06Z

Guenter at 15:39, 19 October 2022

2022-10-19T15:39:49Z

Guenter at 15:09, 19 October 2022

2022-10-19T15:09:10Z

Hwang at 15:21, 9 October 2022

2022-10-09T15:21:30Z

Hwang at 14:52, 9 October 2022

2022-10-09T14:52:02Z

Guenter at 12:37, 10 September 2022

2022-09-10T12:37:16Z

Guenter: Guenter moved page Aufgaben:Aufgabe 1.4: AMI– und MMS43–Code to Aufgaben:Exercise 1.4: AMI and MMS43 Code

2022-09-09T15:24:01Z

Guenter moved page Aufgabe 1.4: AMI– und MMS43–Code to Exercise 1.4: AMI and MMS43 Code

Javier: Text replacement - "Category:Aufgaben zu Beispiele von Nachrichtensystemen" to "Category:Examples of Communication Systems: Exercises"

2021-03-23T12:52:51Z

Text replacement - "Category:Aufgaben zu Beispiele von Nachrichtensystemen" to "Category:Examples of Communication Systems: Exercises"

Javier: Text replacement - "[[Beispiele_von_Nachrichtensystemen" to "[[Examples_of_Communication_Systems"

2020-07-09T12:54:19Z

Text replacement - "[[Beispiele_von_Nachrichtensystemen" to "[[Examples_of_Communication_Systems"

Javier: Text replacement - "[[Digitalsignalübertragung" to "[[Digital_Signal_Transmission"

2020-07-09T12:46:50Z

Text replacement - "[[Digitalsignalübertragung" to "[[Digital_Signal_Transmission"

@@ Line 3: / Line 3: @@
 }}
-[[File:P_ID1582__Bei_A_1_4.png|right|frame|Modified AMI code and MMS43 code]]
+[[File:EN_Bei_A_1_4.png|right|frame|Modified AMI code and MMS43 code]]
 Two different ternary transmission codes are used with ISDN,&nbsp; which are to be clarified in the diagram at an exemplary binary input signal.

@@ Line 69: / Line 69: @@
 {{ML-Kopf}}
-'''(1)'''&nbsp; <u>The first two statements</u> are correct:
+'''(1)'''&nbsp; <u>The first two statements</u>&nbsp; are correct:
-*The modified AMI code is a so-called pseudo-ternary code with $T_{\rm S} = T_{\rm B}$ and symbol-wise coding.
+*The modified AMI code is a pseudo-ternary code with&nbsp; $T_{\rm S} = T_{\rm B}$&nbsp; and symbol-wise coding.&nbsp; The stated assignments apply to the conventional AMI code.
 '''(2)'''&nbsp;
-*The equivalent bit rate of the AMI encoded signal is $R_{\rm C} = {\rm log_2}\hspace{0.05cm}(3)/T_{\rm S}$; the bit rate of the redundancy-free binary source signal is equal to $R_{\rm B} = 1/T_{\rm B}$.
+'''(2)'''&nbsp; The equivalent bit rate of the AMI encoded signal is&nbsp; $R_{\rm C} = {\rm log_2}\hspace{0.05cm}(3)/T_{\rm S}$.
 *With $T_{\rm S} = T_{\rm B}$, according to the chapter [[Digital_Signal_Transmission/Basics_of_Coded_Transmission|"Basics of Coded Transmission"]] of the book "Digital Signal Transmission", we obtain for the (relative) redundancy of the modified AMI code:
 :$$r_{\rm AMI} = \frac{R_{\rm C}-R_{\rm B}}{R_{\rm C}} = 1 - \frac{1}{{\rm ld}\,(3)} \hspace{0.15cm}\underline{\approx 36.9\,\%} \hspace{0.05cm}.$$
-'''(3)'''&nbsp;
+'''(3)'''&nbsp; Using the unit impedance&nbsp; $R = 1 \ \rm \Omega $,&nbsp; the following applies to the transmit power&nbsp; $($with the unit&nbsp; $\rm V^{2})$:
 :$$P_{\rm S,\,AMI} = {1}/{2} \cdot {s_0}^2 = {1}/{2} \cdot {0.75\,{\rm V}}^2 \approx 0.28\,{\rm V^2} \hspace{0.05cm}.$$
-*Here it is considered that the AMI encoded signal is equal to $0 \ \rm V$ in half of the time.
+*Here it is considered that the AMI encoded signal is equal to&nbsp; $0 \ \rm V$&nbsp; in half of the time.
 *Finally, considering the impedance $R = 100 \ \rm \Omega$, we get:
 :$$P_{\rm S,\,AMI} = \frac{0.28\,{\rm V^2}}{100\,\Omega} \hspace{0.15cm}\underline{ = 2.8\,{\rm mW}} \hspace{0.05cm}.$$
-'''(4)'''&nbsp; The MMS43 code actually operates in blocks, with $m_{q} = 4 \ \rm binary \ symbols$ replaced by $m_{c} = 3 \ \rm ternary \ symbols$:
+'''(4)'''&nbsp; The MMS43 code actually operates in blocks,&nbsp; with&nbsp; $m_{q} = 4$&nbsp; binary  symbols&nbsp; replaced by&nbsp; $m_{c} = 3 $&nbsp; ternary  symbols:
 :$$4 \cdot T_{\rm B} = 3 \cdot T_{\rm S}\hspace{0.3cm}\Rightarrow \hspace{0.3cm} T_{\rm S} = {4}/{3} \cdot T_{\rm B} \hspace{0.05cm}.$$
-*Das heißt: That means: The first solution does not apply as well as the last one. Only <u>solution 2</u> is correct:
+*That means:&nbsp; The first solution does not apply as well as the last one.&nbsp; Only&nbsp; <u>solution 2</u>&nbsp; is correct:
 *In block coding, the binary symbol "0" cannot be uniformly replaced by the same code symbol.
-*Rather, the encoding can be described as follows, assuming the running digital sum ${\it \Sigma}_{0} = 0$ at the beginning (see graphic in the information section):
+*In block coding,&nbsp; the binary symbol&nbsp; "0"&nbsp; cannot be uniformly replaced by the same code symbol.&nbsp; Rather,&nbsp; the encoding can be described as follows,&nbsp; assuming the running digital sum&nbsp; ${\it \Sigma}_{0} = 0$&nbsp; at the beginning&nbsp; $($see graphic in the information section$)$:
 :$$\mathbf{0 1 0 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{0 + +}\hspace{0.2cm}({\it \Sigma}_1 = 2)\hspace{0.05cm},$$
 :$$ \mathbf{0 1 1 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{- \,0 \,\,+}\hspace{0.2cm}({\it \Sigma}_2 = 2)\hspace{0.05cm},$$
 :$$ \mathbf{0 1 0 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{- \,0\,\,\, 0}\hspace{0.2cm}({\it \Sigma}_3 = 1) \hspace{0.05cm}.$$
-[[Aufgaben:Exercise_1.4Z:_Modified_MS43_Code|"Exercise 1.4Z"]] discusses the MMS43 code in more detail.
+*[[Aufgaben:Exercise_1.4Z:_Modified_MS43_Code|"Exercise 1.4Z"]]&nbsp; discusses the MMS43 code in more detail.
@@ Line 109: / Line 111: @@
 '''(6)'''&nbsp; The following number of ternary symbols are transmitted on the $\rm U_{K0}$ bus per millisecond:
-*Channel B1: &nbsp;  64 binary symbols &nbsp; &rArr; &nbsp;  48 ternary symbols,
+*Channel B1: &nbsp;  $64$&nbsp; binary symbols &nbsp; &rArr; &nbsp;  $48$&nbsp; ternary symbols,
-*Channel B2: &nbsp;  64 binary symbols &nbsp; &rArr; &nbsp;  48 ternary symbols,
+*Channel B2: &nbsp;  $64$&nbsp; binary symbols &nbsp; &rArr; &nbsp;  $48$&nbsp; ternary symbols,
-*D channel: &nbsp;  16 binary symbols &nbsp; &rArr; &nbsp;  12 ternary symbols,
+*D channel: &nbsp;  $16$&nbsp; binary symbols &nbsp; &rArr; &nbsp;  $12$&nbsp; ternary symbols,
-*Synchronization and control symbols &nbsp; &rArr; &nbsp;  12 ternary symbols.
+*Synchronization and control symbols &nbsp; &rArr; &nbsp;  $12$&nbsp; ternary symbols.
-As a sum, this results in 120 ternary symbols per millisecond or <u>120,000 ternary symbols per second</u>.
+As a sum,&nbsp; this results in&nbsp; $120$&nbsp; ternary symbols per millisecond or&nbsp; $\underline{120,000}$&nbsp; ternary symbols per second.
-'''(7)'''&nbsp; Considering the note in the information section and the larger transmission amplitude $s_{0} = 2.5 \ \rm V$ compared to the (modified) AMI code, we obtain:
+'''(7)'''&nbsp; Considering the note in the information section and the larger transmission amplitude&nbsp; $s_{0} = 2.5 \ \rm V$&nbsp; compared to the&nbsp; (modified)&nbsp; AMI code,&nbsp; we obtain:
 :$$P_{\rm S,\,MMS43} = \frac{2}{3} \cdot \frac{{s_0}^2}{R} = \frac{2}{3} \cdot \frac{({2.5\,{\rm V}})^2}{100\,{\rm \Omega}} \hspace{0.15cm}\underline{\approx 4.2\,{\rm mW}} \hspace{0.05cm}.$$

@@ Line 4: / Line 4: @@
 [[File:P_ID1582__Bei_A_1_4.png|right|frame|Modified AMI code and MMS43 code]]
-Two different ternary transmission codes are used with ISDN, which are to be clarified in the diagram at an exemplary binary input signal.
+Two different ternary transmission codes are used with ISDN,&nbsp; which are to be clarified in the diagram at an exemplary binary input signal.
-The upper diagram shows 12 bits $($each with the bit duration&nbsp; $T_{\rm B})$.&nbsp;
+The upper diagram shows twelve bits&nbsp; $($each with bit duration&nbsp; $T_{\rm B})$.&nbsp;
-*On the&nbsp; $\rm S_{0}$ interface (between NTBA and terminal equipment) the&nbsp; '''modified AMI code''' is used. The difference to the conventional AMI code is the swapping&nbsp; $0 \Leftrightarrow 1$ of the binary input signal.
+*On the&nbsp; $\rm S_{0}$ interface&nbsp; $($between NTBA and terminal equipment$)$,&nbsp; the&nbsp; $\text{modified AMI code}$&nbsp; is used.&nbsp; The difference to the conventional AMI code is the swapping &nbsp; $0 \Leftrightarrow 1$ &nbsp; of the binary input signal.
@@ Line 18: / Line 18: @@
-''Notes:''
+Notes:
 *Information on the AMI code can be found in the chapter&nbsp; [[Digital_Signal_Transmission/Symbolwise_Coding_with_Pseudo-Ternary_Codes|"Symbolwise Coding with Pseudo-Ternary Codes"]]&nbsp; of the same book.
@@ Line 33: / Line 35: @@
 |type="[]"}
 + Symbol duration&nbsp; $T_{\rm S}$&nbsp; and bit duration&nbsp; $T_{\rm B}$&nbsp; of the binary signal are the same.
-+ The encoding is done symbol by symbol.
++ The encoding is done symbol-by-symbol.
-- Each binary&nbsp; "0" is represented by&nbsp; $0 \hspace{0.1cm} \rm V$.&nbsp;
+- Each binary&nbsp; "0"&nbsp; is represented by&nbsp; $0 \hspace{0.1cm} \rm V$.&nbsp;
-- The binary&nbsp; "1" is alternately represented by&nbsp; $+s_{0}$&nbsp; and&nbsp; $-s_{0}$.&nbsp;
+- The binary&nbsp; "1"&nbsp; is alternately represented by&nbsp; $+s_{0}$&nbsp; and&nbsp; $-s_{0}$.&nbsp;
-{What is the relative redundancy of the (modified) AMI code?
+{What is the relative redundancy of the&nbsp; (modified) &nbsp;AMI code?
 |type="{}"}
 $r_{\rm AMI} \ = \ $ { 36.9 3% } $\ \%$
-{Let&nbsp; $s_{0} = 0.75 \hspace{0.1cm} {\rm V}$ and $R = 100 \hspace{0.1cm} {\rm Ω}$ be valid. What is the average transmitted power?
+{Let be&nbsp; $s_{0} = 0.75 \hspace{0.1cm} {\rm V}$&nbsp; and&nbsp; $R = 100 \hspace{0.1cm} {\rm Ω}$.&nbsp; What is the average transmitted power?
 |type="{}"}
 $P_{\rm S, \ AMI} \ = \ $ { 2.8 3% } $\ \rm mW$
@@ Line 48: / Line 50: @@
 |type="[]"}
 - Symbol duration&nbsp; $T_{\rm S}$&nbsp; and bit duration&nbsp; $T_{\rm B}$&nbsp; of the binary signal are the same.
-+ The encoding is done block by block.
++ The encoding is done block-by-block.
 - Each binary&nbsp; "0"&nbsp; is represented by&nbsp; $0 \hspace{0.1cm} \rm V$.&nbsp;
@@ Line 55: / Line 57: @@
 $r_{\rm MMS43} \ = \ $ { 15.9 3% } $\ \%$
-{What is the symbol rate on the&nbsp; $\rm U_{\rm K0}$ bus if there are $12$ ternary synchronization and control symbols to be considered per millisecond?
+{What is the symbol rate on the&nbsp; $\rm U_{\rm K0}$ bus if there are&nbsp; $12$&nbsp; ternary synchronization and control symbols to be considered per millisecond?
 |type="{}"}
 $R_{\rm U_{K0}} \ = \ $ { 120000 3% } $\ \rm ternary \ symbols/second$
-{Let&nbsp; $s_{0} = 2.5 \hspace{0.1cm} {\rm V}$&nbsp; and&nbsp; $R = 100 \hspace{0.1cm} {\rm \Omega }$ be valid. What is the transmit power? <br>''Note:'' &nbsp; For simplicity, assume equally probable ternary symbols.
+{Let be&nbsp; $s_{0} = 2.5 \hspace{0.1cm} {\rm V}$&nbsp; and&nbsp; $R = 100 \hspace{0.1cm} {\rm \Omega }$.&nbsp; What is the transmit power?&nbsp; Note: &nbsp; For simplicity,&nbsp; assume equally probable ternary symbols.
 |type="{}"}
 $P_{\rm S,\ MMS43} \ = \ $ { 4.2 3% } $\ \rm mW$

@@ Line 59: / Line 59: @@
 $R_{\rm U_{K0}} \ = \ $ { 120000 3% } $\ \rm ternary \ symbols/second$
-{Es gelte&nbsp; $s_{0} = 2.5 \hspace{0.1cm} {\rm V}$&nbsp; und&nbsp; $R = 100 \hspace{0.1cm} {\rm \Omega }$. Wie groß ist die Sendeleistung? <br>''Hinweis:'' &nbsp; Gehen Sie vereinfachend von gleichwahrscheinlichen Ternärsymbolen aus.
+{Let&nbsp; $s_{0} = 2.5 \hspace{0.1cm} {\rm V}$&nbsp; and&nbsp; $R = 100 \hspace{0.1cm} {\rm \Omega }$ be valid. What is the transmit power? <br>''Note:'' &nbsp; For simplicity, assume equally probable ternary symbols.
 |type="{}"}
 $P_{\rm S,\ MMS43} \ = \ $ { 4.2 3% } $\ \rm mW$
 </quiz>
-===Musterlösung===
+===Solution===
 {{ML-Kopf}}
-'''(1)'''&nbsp; Richtig sind <u>die zwei ersten Aussagen</u>:
+'''(1)'''&nbsp; <u>The first two statements</u> are correct:
-*Der modifizierte AMI–Code ist ein so genannter Pseudo–Ternärcode mit $T_{\rm S} = T_{\rm B}$ und symbolweiser Codierung.
+*The modified AMI code is a so-called pseudo-ternary code with $T_{\rm S} = T_{\rm B}$ and symbol-wise coding.
-*Die angegebenen Zuordnungen gelten für den herkömmlichen AMI–Code.
+*The stated assignments apply to the conventional AMI code.
-*Dagegen wird beim modifizierten AMI–Code die binäre „1” durch den Spannungswert $0 \ \rm V$ repräsentiert und die binäre „0” alternierend durch $+s_{0}$ bzw. $-s_{0}$, wobei für $s_{0} = 0.75 \ \rm V$ zu setzen ist.
+*On the other hand, in the modified AMI code the binary "1" is represented by the voltage value $0 \ \rm V$ and the binary "0" alternately by $+s_{0}$ bzw. $-s_{0}$, where for $s_{0} = 0.75 \ \rm V$ is to be set.
 '''(2)'''&nbsp;
-*Die äquivalente Bitrate des AMI–codierten Signals beträgt $R_{\rm C} = {\rm log_2}\hspace{0.05cm}(3)/T_{\rm S}$; die Bitrate des redundanzfreien binären Quellensignals ist gleich $R_{\rm B} = 1/T_{\rm B}$.
+*The equivalent bit rate of the AMI encoded signal is $R_{\rm C} = {\rm log_2}\hspace{0.05cm}(3)/T_{\rm S}$; the bit rate of the redundancy-free binary source signal is equal to $R_{\rm B} = 1/T_{\rm B}$.
-*Mit $T_{\rm S} = T_{\rm B}$ erhält man entsprechend dem Kapitel [[Digital_Signal_Transmission/Grundlagen_der_codierten_Übertragung|Grundlagen der codierten Übertragung]] des Buches „Digitalsignalübertragung” für die (relative) Redundanz des modifizierten AMI–Codes:
+*With $T_{\rm S} = T_{\rm B}$, according to the chapter [[Digital_Signal_Transmission/Basics_of_Coded_Transmission|"Basics of Coded Transmission"]] of the book "Digital Signal Transmission", we obtain for the (relative) redundancy of the modified AMI code:
 :$$r_{\rm AMI} = \frac{R_{\rm C}-R_{\rm B}}{R_{\rm C}} = 1 - \frac{1}{{\rm ld}\,(3)} \hspace{0.15cm}\underline{\approx 36.9\,\%} \hspace{0.05cm}.$$
 '''(3)'''&nbsp;
-*Unter Verwendung des Einheitswiderstandes $R = 1 \ \rm \Omega $ gilt für die Sendeleistung (mit der Einheit $\rm V^{2}$):
+*Using the unit impedance $R = 1 \ \rm \Omega $, the following applies to the transmit power (with the unit $\rm V^{2}$):
 :$$P_{\rm S,\,AMI} = {1}/{2} \cdot {s_0}^2 = {1}/{2} \cdot {0.75\,{\rm V}}^2 \approx 0.28\,{\rm V^2} \hspace{0.05cm}.$$
-*Hierbei ist berücksichtigt, dass das AMI–codierte Signal in der Hälfte der Zeit gleich $0 \ \rm V$ ist.
+*Here it is considered that the AMI encoded signal is equal to $0 \ \rm V$ in half of the time.
-*Bei Berücksichtigung des Widerstandes $R = 100 \ \rm \Omega$ ergibt sich schließlich:
+*Finally, considering the impedance $R = 100 \ \rm \Omega$, we get:
 :$$P_{\rm S,\,AMI} = \frac{0.28\,{\rm V^2}}{100\,\Omega} \hspace{0.15cm}\underline{ = 2.8\,{\rm mW}} \hspace{0.05cm}.$$
-'''(4)'''&nbsp; Der MMS43–Code arbeitet tatsächlich blockweise, wobei $m_{q} = 4 \ \rm Binärsymbole$ durch  $m_{c} = 3 \ \rm Ternärsymbole$ ersetzt werden:
+'''(4)'''&nbsp; The MMS43 code actually operates in blocks, with $m_{q} = 4 \ \rm binary \ symbols$ replaced by $m_{c} = 3 \ \rm ternary \ symbols$:
 :$$4 \cdot T_{\rm B} = 3 \cdot T_{\rm S}\hspace{0.3cm}\Rightarrow \hspace{0.3cm} T_{\rm S} = {4}/{3} \cdot T_{\rm B} \hspace{0.05cm}.$$
-*Das heißt: Der erste Lösungsvorschlag trifft nicht zu ebenso wie der letzte. Richtig ist nur der  <u>Vorschlag 2</u>:
+*Das heißt: That means: The first solution does not apply as well as the last one. Only <u>solution 2</u> is correct:
-*Bei Blockcodierung kann das Binärsymbol „0” nicht einheitlich durch das gleiche Codesymbol ersetzt werden.
+*In block coding, the binary symbol "0" cannot be uniformly replaced by the same code symbol.
-*Vielmehr lässt sich die Codierung wie folgt beschreiben, wenn man zu Beginn von der laufenden digitalen Summe ${\it \Sigma}_{0} = 0$ ausgeht (siehe Grafik auf der Angabenseite):
+*Rather, the encoding can be described as follows, assuming the running digital sum ${\it \Sigma}_{0} = 0$ at the beginning (see graphic in the information section):
 :$$\mathbf{0 1 0 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{0 + +}\hspace{0.2cm}({\it \Sigma}_1 = 2)\hspace{0.05cm},$$
 :$$ \mathbf{0 1 1 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{- \,0 \,\,+}\hspace{0.2cm}({\it \Sigma}_2 = 2)\hspace{0.05cm},$$
 :$$ \mathbf{0 1 0 1} \hspace{0.1cm} \ \Rightarrow \ \hspace{0.1cm}\mathbf{- \,0\,\,\, 0}\hspace{0.2cm}({\it \Sigma}_3 = 1) \hspace{0.05cm}.$$
-In der [[Aufgaben:Aufgabe_1.4Z:_Modifizierter_MS43–Code|Aufgabe 1.4Z]] wird der MMS43–Code noch ausführlicher behandelt.
+[[Aufgaben:Exercise_1.4Z:_Modified_MS43_Code|"Exercise 1.4Z"]] discusses the MMS43 code in more detail.
-'''(5)'''&nbsp;  Der MMS43–Code gehört zur Klasse der 4B3T–Codes. Für diese gilt:
+'''(5)'''&nbsp; The MMS43 code belongs to the class of 4B3T codes. For these it is valid:
 :$$R_{\rm B} = \frac{1}{T_{\rm B}}, \hspace{0.2cm} R_{\rm C} = \frac{{\rm ld}\,(3)}{T_{\rm S}}\hspace{0.3cm}
 \Rightarrow \hspace{0.3cm}r_{\rm MMS43} = 1 - \frac{R_{\rm B}}{R_{\rm C}} = 1 - \frac{T_{\rm S}/T_{\rm B}}{{\rm ld}\,(3)} = 1 - \frac{4/3}{{\rm log_2}\,(3)} \hspace{0.15cm}\underline{\approx 15.9\,\%} \hspace{0.05cm}.$$
@@ Line 106: / Line 106: @@
-'''(6)'''&nbsp; Pro Millisekunde werden auf dem $\rm U_{K0}$–Bus die folgende Anzahl an Ternärsymbolen übertragen:
+'''(6)'''&nbsp; The following number of ternary symbols are transmitted on the $\rm U_{K0}$ bus per millisecond:
-*Kanal B1: &nbsp;  64 Binärsymbole &nbsp; &rArr; &nbsp;  48 Ternärsymbole,
+*Channel B1: &nbsp;  64 binary symbols &nbsp; &rArr; &nbsp;  48 ternary symbols,
-*Kanal B2: &nbsp;  64 Binärsymbole &nbsp; &rArr; &nbsp;  48 Ternärsymbole,
+*Channel B2: &nbsp;  64 binary symbols &nbsp; &rArr; &nbsp;  48 ternary symbols,
-*D–Kanal: &nbsp;  16 Binärsymbole &nbsp; &rArr; &nbsp;  12 Ternärsymbole,
+*D channel: &nbsp;  16 binary symbols &nbsp; &rArr; &nbsp;  12 ternary symbols,
-*Synchronisations– und Steuersymbole &nbsp; &rArr; &nbsp;  12 Ternärsymbole.
+*Synchronization and control symbols &nbsp; &rArr; &nbsp;  12 ternary symbols.
-Dies ergibt als Summe 120 Ternärsymbole pro Millisekunde bzw. <u>120 000  Ternärsymbole pro Sekunde</u>.
+As a sum, this results in 120 ternary symbols per millisecond or <u>120,000 ternary symbols per second</u>.
-'''(7)'''&nbsp; Unter Berücksichtigung des Hinweises auf der Angabenseite und der gegenüber dem (modifizierten) AMI–Code größeren Sendeamplitude $s_{0} = 2.5 \ \rm V$ erhält man:
+'''(7)'''&nbsp; Considering the note in the information section and the larger transmission amplitude $s_{0} = 2.5 \ \rm V$ compared to the (modified) AMI code, we obtain:
 :$$P_{\rm S,\,MMS43} = \frac{2}{3} \cdot \frac{{s_0}^2}{R} = \frac{2}{3} \cdot \frac{({2.5\,{\rm V}})^2}{100\,{\rm \Omega}} \hspace{0.15cm}\underline{\approx 4.2\,{\rm mW}} \hspace{0.05cm}.$$

@@ Line 1: / Line 1: @@
-{{quiz-Header|Buchseite=Beispiele von Nachrichtensystemen/ISDN-Basisanschluss
+{{quiz-Header|Buchseite=Examples_of_Communication_Systems/ISDN_Basic_Access
 }}
-[[File:P_ID1582__Bei_A_1_4.png|right|frame|Modifizierter AMI&ndash;Code und MMS43&ndash;Code]]
+[[File:P_ID1582__Bei_A_1_4.png|right|frame|Modified AMI code and MMS43 code]]
-Bei ISDN werden zwei verschiedene ternäre Übertragungscodes eingesetzt, die in der Grafik an einem beispielhaften binären Eingangssignal verdeutlicht werden sollen.
+Two different ternary transmission codes are used with ISDN, which are to be clarified in the diagram at an exemplary binary input signal.
-Im oberen Diagramm sind 12 Bit $($jeweils mit der Bitdauer&nbsp; $T_{\rm B})$&nbsp; dargestellt.
+The upper diagram shows 12 bits $($each with the bit duration&nbsp; $T_{\rm B})$.&nbsp;
-*Auf der&nbsp; $\rm S_{0}$–Schnittstelle (zwischen NTBA und Endgerät) verwendet man wird den&nbsp; '''modifizierten AMI–Code'''. Der Unterschied zum herkömmlichen AMI–Code ist die Vertauschung&nbsp; $0 \Leftrightarrow 1$ des binären Eingangssignals.
+*On the&nbsp; $\rm S_{0}$ interface (between NTBA and terminal equipment) the&nbsp; '''modified AMI code''' is used. The difference to the conventional AMI code is the swapping&nbsp; $0 \Leftrightarrow 1$ of the binary input signal.
-*Dagegen wird auf der&nbsp; $\rm U_{K0}$–Schnittstelle der&nbsp; '''MMS43–Code''' &nbsp;('''M'''odified '''M'''onitoring '''S'''um '''4'''B'''3'''T) eingesetzt, wobei jeweils vier Binärsymbole durch drei Ternärsymbole $($Spannungswerte &nbsp;$0 \ {\rm V}, +2.5 \ {\rm V}$&nbsp; und&nbsp; $-2.5 \ {\rm V})$&nbsp; ersetzt werden. Die Zuordnung erfolgt abhängig von den vorher codierten Symbolen.
+*In contrast, the &nbsp; '''MMS43 code''' &nbsp;('''M'''odified '''M'''onitoring '''S'''um '''4'''B'''3'''T) is used on the &nbsp; $\rm U_{K0}$ interface, where four binary symbols are replaced by three ternary symbols $($voltage values &nbsp;$0 \ {\rm V}, +2.5 \ {\rm V}$&nbsp; and&nbsp; $-2.5 \ {\rm V})$.&nbsp; The assignment is done depending on the previously coded symbols.
@@ Line 18: / Line 18: @@
-''Hinweise:''
+''Notes:''
-*Die Aufgabe gehört zum Kapitel&nbsp; [[Examples_of_Communication_Systems/ISDN-Basisanschluss|ISDN-Basisanschluss]].
+*The exercise belongs to the chapter&nbsp; [[Examples_of_Communication_Systems/ISDN_Basic_Access|"ISDN Basic Access"]].
-*Angaben zum MMS43–Code finden Sie im Kapitel&nbsp;  [[Digital_Signal_Transmission/Blockweise_Codierung_mit_4B3T-Codes|Blockweise Codierung mit 4B3T-Codes]]&nbsp; des Buches „Digitalsignalübertragung”.
+*Information on the MMS43 code can be found in the chapter&nbsp;  [[Digital_Signal_Transmission/Block_Coding_with_4B3T_Codes|"Block Coding with 4B3T Codes"]]&nbsp; of the book "Digital Signal Transmission".
-*Angaben zum AMI–Code gibt es im Kapitel&nbsp; [[Digital_Signal_Transmission/Symbolweise_Codierung_mit_Pseudoternärcodes|Symbolweise Codierung mit Pseudoternärcodes]]&nbsp; des gleichen Buches.
+*Information on the AMI code can be found in the chapter&nbsp; [[Digital_Signal_Transmission/Symbolwise_Coding_with_Pseudo-Ternary_Codes|"Symbolwise Coding with Pseudo-Ternary Codes"]]&nbsp; of the same book.
-===Fragebogen===
+===Questions===
 <quiz display=simple>
-{Welche Eigenschaften weist der modifizierte AMI–Code auf?
+{What are the properties of the modified AMI code?
 |type="[]"}
-+ Symboldauer&nbsp; $T_{\rm S}$&nbsp; und Bitdauer&nbsp; $T_{\rm B}$&nbsp; des Binärsignals sind gleich.
++ Symbol duration&nbsp; $T_{\rm S}$&nbsp; and bit duration&nbsp; $T_{\rm B}$&nbsp; of the binary signal are the same.
-+ Die Codierung geschieht symbolweise.
++ The encoding is done symbol by symbol.
-- Jede binäre&nbsp; „0”&nbsp; wird durch&nbsp; $0 \hspace{0.1cm} \rm V$&nbsp; dargestellt.
+- Each binary&nbsp; "0" is represented by&nbsp; $0 \hspace{0.1cm} \rm V$.&nbsp;
-- Die binäre&nbsp; „1”&nbsp; wird alternierend mit&nbsp; $+s_{0}$&nbsp; und&nbsp; $-s_{0}$&nbsp; repräsentiert.
+- The binary&nbsp; "1" is alternately represented by&nbsp; $+s_{0}$&nbsp; and&nbsp; $-s_{0}$.&nbsp;
-{Wie groß ist die relative  Redundanz des (modifizierten) AMI–Codes?
+{What is the relative redundancy of the (modified) AMI code?
 |type="{}"}
 $r_{\rm AMI} \ = \ $ { 36.9 3% } $\ \%$
-{Es gelte&nbsp; $s_{0} = 0.75 \hspace{0.1cm} {\rm V}$ und $R = 100 \hspace{0.1cm} {\rm Ω}$. Wie groß ist die mittlere Sendeleistung?
+{Let&nbsp; $s_{0} = 0.75 \hspace{0.1cm} {\rm V}$ and $R = 100 \hspace{0.1cm} {\rm Ω}$ be valid. What is the average transmitted power?
 |type="{}"}
 $P_{\rm S, \ AMI} \ = \ $ { 2.8 3% } $\ \rm mW$
-{Welche Eigenschaften zeigt der MMS43–Code?
+{Which properties does the MMS43 code show?
 |type="[]"}
-- Symboldauer&nbsp; $T_{\rm S}$&nbsp; und Bitdauer&nbsp; $T_{\rm B}$&nbsp; des Binärsignals sind gleich.
+- Symbol duration&nbsp; $T_{\rm S}$&nbsp; and bit duration&nbsp; $T_{\rm B}$&nbsp; of the binary signal are the same.
-+ Die Codierung erfolgt blockweise.
++ The encoding is done block by block.
-- Jede binäre&nbsp; „0”&nbsp; wird durch&nbsp; $0 \hspace{0.1cm} \rm V$&nbsp; dargestellt.
+- Each binary&nbsp; "0"&nbsp; is represented by&nbsp; $0 \hspace{0.1cm} \rm V$.&nbsp;
-{Wie groß ist die relative Redundanz des MMS43–Codes?
+{What is the relative redundancy of the MMS43 code?
 |type="{}"}
 $r_{\rm MMS43} \ = \ $ { 15.9 3% } $\ \%$
-{Wie groß ist die Symbolrate auf dem&nbsp; $\rm U_{\rm K0}$–Bus, wenn pro Millisekunde $12$ ternäre Synchronisations– und Steuersymbole zu berücksichtigen sind?
+{What is the symbol rate on the&nbsp; $\rm U_{\rm K0}$ bus if there are $12$ ternary synchronization and control symbols to be considered per millisecond?
 |type="{}"}
-$R_{\rm U_{K0}} \ = \ $ { 120000 3% } $\ \rm Ternärsymbole/Sekunde$
+$R_{\rm U_{K0}} \ = \ $ { 120000 3% } $\ \rm ternary \ symbols/second$
 {Es gelte&nbsp; $s_{0} = 2.5 \hspace{0.1cm} {\rm V}$&nbsp; und&nbsp; $R = 100 \hspace{0.1cm} {\rm \Omega }$. Wie groß ist die Sendeleistung? <br>''Hinweis:'' &nbsp; Gehen Sie vereinfachend von gleichwahrscheinlichen Ternärsymbolen aus.

← Older revision		Revision as of 12:37, 10 September 2022
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−	[[Category:Examples of Communication Systems: Exercises\|^1.2 ISDN~~-Basisanschluss~~^]]	+	[[Category:Examples of Communication Systems: Exercises\|^1.2 ISDN Basic Access^]]

← Older revision	Revision as of 15:24, 9 September 2022
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← Older revision		Revision as of 12:52, 23 March 2021
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−	[[Category:~~Aufgaben zu Beispiele von Nachrichtensystemen~~\|^1.2 ISDN-Basisanschluss^]]	+	[[Category:Examples of Communication Systems: Exercises\|^1.2 ISDN-Basisanschluss^]]