Discrete Memoryless Sources

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# OVERVIEW OF THE FIRST MAIN CHAPTER #


This first chapter describes the calculation and the meaning of entropy.  According to the Shannonian information definition, entropy is a measure of the mean uncertainty about the outcome of a statistical event or the uncertainty in the measurement of a stochastic quantity.  Somewhat casually expressed, the entropy of a random quantity quantifies its "randomness".

In detail are discussed:

  • The  decision content  and the  entropy  of a  "Discrete Memoryless Source",
  • the binary entropy function  and its application to non-binary sources,
  • the entropy calculation for memory sources  and suitable approximations,
  • the peculiarities of Markov sources  regarding the entropy calculation,
  • the procedure for sources with a large number of symbols, for example natural texts,
  • the entropy estimates  according to Shannon and Küpfmüller.


Model and requirements


We consider a value discrete message source  $\rm Q$, which gives a sequence  $ \langle q_ν \rangle$  of symbols.

  • For the run variable  $ν = 1$, ... , $N$, where  $N$  should be "sufficiently large".
  • Each individual source symbol  $q_ν$  comes from a symbol set  $\{q_μ \}$  where  $μ = 1$, ... , $M$, where  $M$  denotes the symbol range:
$$q_{\nu} \in \left \{ q_{\mu} \right \}, \hspace{0.25cm}{\rm with}\hspace{0.25cm} \nu = 1, \hspace{0.05cm} \text{ ...}\hspace{0.05cm} , N\hspace{0.25cm}{\rm and}\hspace{0.25cm}\mu = 1,\hspace{0.05cm} \text{ ...}\hspace{0.05cm} , M \hspace{0.05cm}.$$

The figure shows a quaternary message source  $(M = 4)$  with the alphabet  $\rm \{A, \ B, \ C, \ D\}$  and an exemplary sequence of length  $N = 100$.

Memoryless Quaternary Message Source

The following requirements apply:

  • The quaternary news source is fully described by  $M = 4$  symbol probabilities  $p_μ$.  In general it applies:
$$\sum_{\mu = 1}^M \hspace{0.1cm}p_{\mu} = 1 \hspace{0.05cm}.$$
$${\rm Pr} \left (q_{\nu} = q_{\mu} \right ) = {\rm Pr} \left (q_{\nu} = q_{\mu} \hspace{0.03cm} | \hspace{0.03cm} q_{\nu -1}, q_{\nu -2}, \hspace{0.05cm} \text{ ...}\hspace{0.05cm}\right ) \hspace{0.05cm}.$$
  • Since the alphabet consists of symbols  (and not of random variables) , the specification of  expected values  (linear mean, quadratic mean, dispersion, etc.) is not possible here, but also not necessary from an information-theoretical point of view.


These properties will now be illustrated with an example.

Relative frequencies as a function of  $N$

$\text{Example 1:}$  For the symbol probabilities of a quaternary source applies:

$$p_{\rm A} = 0.4 \hspace{0.05cm},\hspace{0.2cm}p_{\rm B} = 0.3 \hspace{0.05cm},\hspace{0.2cm}p_{\rm C} = 0.2 \hspace{0.05cm},\hspace{0.2cm} p_{\rm D} = 0.1\hspace{0.05cm}.$$

For an infinitely long sequence  $(N \to \infty)$

  • the  relative frequencies  $h_{\rm A}$,  $h_{\rm B}$,  $h_{\rm C}$,  $h_{\rm D}$   ⇒   a-posteriori parameters
  • were identical to the  probabilities  $p_{\rm A}$,  $p_{\rm B}$,  $p_{\rm C}$,  $p_{\rm D}$   ⇒   a-priori parameters.


With smaller  $N$  deviations may occur, as the adjacent table (result of a simulation) shows.

  • In the graphic above an exemplary sequence is shown with  $N = 100$  symbols.
  • Due to the set elements  $\rm A$,  $\rm B$,  $\rm C$  and  $\rm D$  no mean values can be given.


However, if you replace the symbols with numerical values, for example  $\rm A \Rightarrow 1$,   $\rm B \Rightarrow 2$,   $\rm C \Rightarrow 3$,   $\rm D \Rightarrow 4$, then you will get
    time averaging   ⇒   crossing line     or     ensemble averaging   ⇒   expected value formation

$$m_1 = \overline { q_{\nu} } = {\rm E} \big [ q_{\mu} \big ] = 0.4 \cdot 1 + 0.3 \cdot 2 + 0.2 \cdot 3 + 0.1 \cdot 4 = 2 \hspace{0.05cm},$$
$$m_2 = \overline { q_{\nu}^{\hspace{0.05cm}2} } = {\rm E} \big [ q_{\mu}^{\hspace{0.05cm}2} \big ] = 0.4 \cdot 1^2 + 0.3 \cdot 2^2 + 0.2 \cdot 3^2 + 0.1 \cdot 4^2 = 5 \hspace{0.05cm},$$
$$\sigma = \sqrt {m_2 - m_1^2} = \sqrt {5 - 2^2} = 1 \hspace{0.05cm}.$$


Decision content - Message content


Claude Elwood Shannon  defined in 1948 in the standard work of information theory  [Sha48][1]  the concept of information as "decrease of uncertainty about the occurrence of a statistical event".

Let us make a mental experiment with  $M$  possible results, which are all equally probable:   $p_1 = p_2 = \hspace{0.05cm} \text{ ...}\hspace{0.05cm} = p_M = 1/M \hspace{0.05cm}.$

Under this assumption applies:

  • Is  $M = 1$, then each individual attempt will yield the same result and therefore there is no uncertainty about the output.
  • On the other hand, an observer learns about an experiment with  $M = 2$, for example the "coin toss" with the set of events  $\big \{\rm \boldsymbol{\rm Z}, \rm \boldsymbol{\rm W} \big \}$  and the probabilities  $p_{\rm Z} = p_{\rm W} = 0. 5$, a gain in information; The uncertainty regarding  $\rm Z$  resp.  $\rm W$  is resolved.
  • In the experiment "dice"  $(M = 6)$  and even more in roulette  $(M = 37)$  the gained information is even more significant for the observer than in the "coin toss" when he learns which number was thrown or which ball fell.
  • Finally it should be considered that the experiment  "triple coin toss"  with the  $M = 8$  possible results  $\rm ZZZ$,  $\rm ZZW$,  $\rm ZWZ$,  $\rm ZWW$,  $\rm WZZ$,  $\rm WZW$,  $\rm WWZ$,  $\rm WWW$  provides three times the information as the single coin toss  $(M = 2)$.


The following definition fulfills all the requirements listed here for a quantitative information measure for equally probable events, indicated only by the symbol range  $M$.

$\text{Definition:}$  The  decision content   of a message source depends only on the symbol range  $M$  and results in

$$H_0 = {\rm log}\hspace{0.1cm}M = {\rm log}_2\hspace{0.1cm}M \hspace{0.15cm} {\rm (in \ “bit")} = {\rm ln}\hspace{0.1cm}M \hspace{0.15cm}\text {(in “nat")} = {\rm lg}\hspace{0.1cm}M \hspace{0.15cm}\text {(in “Hartley")}\hspace{0.05cm}.$$
  • The term  message content is also commonly used for this.
  • Since  $H_0$  indicates the maximum value of the  Entropy  $H$ , $H_\text{max}$  is also used in our tutorial as short notation .


Please note our nomenclature:

  • The logarithm will be called "log" in the following, independent of the base.
  • The relations mentioned above are fulfilled due to the following properties:
$${\rm log}\hspace{0.1cm}1 = 0 \hspace{0.05cm},\hspace{0.2cm} {\rm log}\hspace{0.1cm}37 > {\rm log}\hspace{0.1cm}6 > {\rm log}\hspace{0.1cm}2\hspace{0.05cm},\hspace{0.2cm} {\rm log}\hspace{0.1cm}M^k = k \cdot {\rm log}\hspace{0.1cm}M \hspace{0.05cm}.$$
  • Usually we use the logarithm to the base  $2$   ⇒   Logarithm dualis  $\rm (ld)$, where the pseudo unit "bit", more precisely:  "bit/symbol", is then added:
$${\rm ld}\hspace{0.1cm}M = {\rm log_2}\hspace{0.1cm}M = \frac{{\rm lg}\hspace{0.1cm}M}{{\rm lg}\hspace{0.1cm}2} = \frac{{\rm ln}\hspace{0.1cm}M}{{\rm ln}\hspace{0.1cm}2} \hspace{0.05cm}.$$
  • In addition, you can find in the literature some additional definitions, which are based on the natural logarithm  $\rm (ln)$  or the logarithm  $\rm (lg)$ .

Information content and entropy


We now waive the previous requirement that all  $M$  possible results of an experiment are equally probable.  In order to keep the spelling as compact as possible, we define for this page only:

$$p_1 > p_2 > \hspace{0.05cm} \text{ ...}\hspace{0.05cm} > p_\mu > \hspace{0.05cm} \text{ ...}\hspace{0.05cm} > p_{M-1} > p_M\hspace{0.05cm},\hspace{0.4cm}\sum_{\mu = 1}^M p_{\mu} = 1 \hspace{0.05cm}.$$

We now consider the information content  of the individual symbols, where we denote the "logarithm dualis" with $\log_2$:

$$I_\mu = {\rm log_2}\hspace{0.1cm}\frac{1}{p_\mu}= -\hspace{0.05cm}{\rm log_2}\hspace{0.1cm}{p_\mu} \hspace{0.5cm}{\rm (unit\hspace{-0.15cm}: \hspace{0.15cm}bit\hspace{0.15cm}or\hspace{0.15cm}bit/Symbol)} \hspace{0.05cm}.$$

You can see:

  • because of  $p_μ ≤ 1$  the information content is never negative.  In the borderline case  $p_μ \to 1$  goes  $I_μ \to 0$.
  • However for  $I_μ = 0$   ⇒   $p_μ = 1$   ⇒   $M = 1$  the decision content is also  $H_0 = 0$.
  • For decreasing probabilities  $p_μ$  the information content increases continuously:
$$I_1 < I_2 < \hspace{0.05cm} \text{ ...}\hspace{0.05cm} < I_\mu <\hspace{0.05cm} \text{ ...}\hspace{0.05cm} < I_{M-1} < I_M \hspace{0.05cm}.$$

$\text{Conclusion:}$  The more improbable an event is, the greater is its information content.  This fact is also found in daily life:

  • "6 right ones" in the lottery are more likely to be noticed than "3 right ones" or no win at all.
  • A tsunami in Asia also dominates the news in Germany for weeks as opposed to the almost standard Deutsche Bahn delays.
  • A series of defeats of Bayern Munich leads to huge headlines in contrast to a winning series.  With 1860 Munich exactly the opposite is the case.


However, the information content of a single symbol (or event) is not very interesting.  On the other hand

  • by ensemble averaging over all possible symbols  $q_μ$  bzw. 
  • by time averaging over all elements of the sequence  $\langle q_ν \rangle$

one of the central variables of information theory.

$\text{Definition:}$  The  Entropy  $H$  of a source indicates the mean information content of all symbols :

$$H = \overline{I_\nu} = {\rm E}\hspace{0.01cm}[I_\mu] = \sum_{\mu = 1}^M p_{\mu} \cdot {\rm log_2}\hspace{0.1cm}\frac{1}{p_\mu}= -\sum_{\mu = 1}^M p_{\mu} \cdot{\rm log_2}\hspace{0.1cm}{p_\mu} \hspace{0.5cm}\text{(unit: bit, more precisely: bit/symbol)} \hspace{0.05cm}.$$

The overline marks again a time averaging and  $\rm E[\text{...}]$  a ensemble averaging.


Entropy is among other things a measure for

  • the mean uncertainty about the outcome of a statistical event,
  • the "randomness" of this event,  and
  • the average information content of a random variable.


Binary entropy function


At first we will restrict ourselves to the special case  $M = 2$  and consider a binary source, which returns the two symbols  $\rm A$  and  $\rm B$    The occurrence probabilities are   $p_{\rm A} = p$  and  $p_{\rm B} = 1 - p$.

For the entropy of this binary source applies:

$$H_{\rm bin} (p) = p \cdot {\rm log_2}\hspace{0.1cm}\frac{1}{\hspace{0.1cm}p\hspace{0.1cm}} + (1-p) \cdot {\rm log_2}\hspace{0.1cm}\frac{1}{1-p} \hspace{0.5cm}{\rm (unit\hspace{-0.15cm}: \hspace{0.15cm}bit\hspace{0.15cm}or\hspace{0.15cm}bit/Symbol)} \hspace{0.05cm}.$$

The function is called  $H_\text{bin}(p)$  the  binary entropy function.  The entropy of a source with a larger symbol range  $M$  can often be expressed using  $H_\text{bin}(p)$ .

$\text{Example 2:}$  The figure shows the binary entropy function for the values  $0 ≤ p ≤ 1$  of the symbol probability of  $\rm A$  $($or also of  $\rm B)$.  You can see

Binary entropy function as function of  $p$
  • The maximum value  $H_\text{max} = 1\; \rm bit$  results for  $p = 0.5$, thus for equally probable binary symbols.  Then   $\rm A$  and  $\rm B$  contribute the same amount to entropy.
  • $H_\text{bin}(p)$  is symmetrical about  $p = 0.5$.  A source with  $p_{\rm A} = 0.1$  and  $p_{\rm B} = 0. 9$  has the same entropy  $H = 0.469 \; \rm bit$  as a source with  $p_{\rm A} = 0.9$  and  $p_{\rm B} = 0.1$.
  • The difference  $ΔH = H_\text{max} - H$ gives  the  redundancy  of the source and  $r = ΔH/H_\text{max}$  the  relative redundancy.   In the example,  $ΔH = 0.531\; \rm bit$  and  $r = 53.1 \rm \%$.
  • For  $p = 0$  this results in  $H = 0$, since the symbol sequence  $\rm B \ B \ B \text{...}$  can be predicted with certainty.   Actually, the symbol range is now only  $M = 1$.  The same applies to  $p = 1$   ⇒   symbol sequence  $\rm A \ A \ A \ text{...}$.
  • $H_\text{bin}(p)$  is always a  concave function, since the second derivative after the parameter  $p$  is negative for all values of  $p$ :
$$\frac{ {\rm d}^2H_{\rm bin} (p)}{ {\rm d}\,p^2} = \frac{- 1}{ {\rm ln}(2) \cdot p \cdot (1-p)}< 0 \hspace{0.05cm}.$$

Message sources with a larger symbol range


In the  first section  of this chapter we have a quaternary message source  $(M = 4)$  with the symbol probabilities  $p_{\rm A} = 0. 4$,   $p_{\rm B} = 0.3$,   $p_{\rm C} = 0.2$   and  $ p_{\rm D} = 0.1$  considered.  This source has the following entropy:

$$H_{\rm quat} = 0.4 \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{0.4} + 0.3 \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{0. 3} + 0.2 \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{0.2}+ 0.1 \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{0.1}.$$

For numerical calculation, the detour via the decimal logarithm  $\lg \ x = {\rm log}_{10} \ x$ , is often necessary. Since the logarithm dualis  $ {\rm log}_2 \ x$  is mostly not found on pocket calculators.

$$H_{\rm quat}=\frac{1}{{\rm lg}\hspace{0.1cm}2} \cdot \left [ 0.4 \cdot {\rm lg}\hspace{0.1cm}\frac{1}{0.4} + 0.3 \cdot {\rm lg}\hspace{0.1cm}\frac{1}{0. 3} + 0.2 \cdot {\rm lg}\hspace{0.1cm}\frac{1}{0.2} + 0.1 \cdot {\rm lg}\hspace{0.1cm}\frac{1}{0.1} \right ] = 1.845\,{\rm bit} \hspace{0.05cm}.$$

$\text{Example 3:}$  Now there are certain symmetries between the symbol probabilities:

Entropy of binary source and quaternary source
$$p_{\rm A} = p_{\rm D} = p \hspace{0.05cm},\hspace{0.4cm}p_{\rm B} = p_{\rm C} = 0.5 - p \hspace{0.05cm},\hspace{0.3cm}{\rm with} \hspace{0.15cm}0 \le p \le 0.5 \hspace{0.05cm}.$$

In this case, the binary entropy function can be used to calculate the entropy:

$$H_{\rm quat} = 2 \cdot p \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{\hspace{0.1cm}p\hspace{0.1cm} } + 2 \cdot (0.5-p) \cdot {\rm log}_2\hspace{0.1cm}\frac{1}{0.5-p}$$

$$\Rightarrow \hspace{0.3cm} H_{\rm quat} = 1 + H_{\rm bin}(2p) \hspace{0.05cm}.$$

The graphic shows as a function of  $p$

  • the entropy of the quaternary source (blue)
  • in comparison to the entropy course of the binary source (red).


For the quaternary source only the abscissa  $0 ≤ p ≤ 0.5$  is allowed.
You can see from the blue curve for the quaternary source:

  • The maximum entropy  $H_\text{max} = 2 \; \rm bit/symbol$  results for  $p = 0.25$   ⇒   equally probable symbols:   $p_{\rm A} = p_{\rm B} = p_{\rm C} = p_{\rm A} = 0.25$.
  • With  $p = 0$  resp.  $p = 0.5$  the quaternary source degenerates to a binary source with  $p_{\rm B} = p_{\rm C} = 0. 5$  and  $p_{\rm A} = p_{\rm D} = 0$   ⇒   entropy  $H = 1 \; \rm bit/symbol$.
  • The source with  $p_{\rm A} = p_{\rm D} = 0.1$  and  $p_{\rm B} = p_{\rm C} = 0.4$  has the following characteristics (each with the pseudo unit "bit/symbol"):
    (1)   entropy:   $H = 1 + H_{\rm bin} (2p) =1 + H_{\rm bin} (0.2) = 1.722,$
    (2)   Redundancy:   ${\rm \Delta }H = {\rm log_2}\hspace{0.1cm} M - H =2- 1.722= 0.278,$
    (3)   relative redundancy:   $r ={\rm \delta }H/({\rm log_2}\hspace{0.1cm} M) = 0.139\hspace{0.05cm}.$
  • The redundancy of the quaternary source with  $p = 0.1$  is equal to  $ΔH = 0.278 \; \rm bit/symbol$  and thus exactly the same as the redundancy of the binary source with  $p = 0.2$.


Exercises for the chapter


Exercise 1.1: Entropy of the Weather

Aufgabe 1.1Z: Binäre Entropiefunktion

Aufgabe 1.2: Entropie von Ternärquellen


List of sources

  1. Shannon, C.E.: A Mathematical Theory of Communication. In: Bell Syst. Techn. J. 27 (1948), pp. 379-423 and pp. 623-656.