[[File:P_ID254__Sto_A_4_3Tab.png|right|frame|Table for moment calculation]]
A "clocked" random number generator returns a sequence $\langle x_\nu \rangle$ of binary random numbers.
A "clocked" random number generator returns a sequence $\langle x_\nu \rangle$ of binary random numbers.
*It is assumed that the binary numbers $0$ and $1$ occur with equal probabilities and that the individual random numbers do not depend on each other.
*It is assumed that the binary numbers $0$ and $1$ occur with equal probabilities and that the individual random numbers do not depend on each other.
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:$$a_\nu=x_\nu+x_{\nu-1}+x_{\nu-2},$$
:$$a_\nu=x_\nu+x_{\nu-1}+x_{\nu-2},$$
*the "modulo 2 sum" $m_\nu$:
*the "modulo–2 sum" $m_\nu$:
:$$m_\nu=x_\nu\oplus x_{\nu-1}\oplus x_{\nu-2}.$$
:$$m_\nu=x_\nu\oplus x_{\nu-1}\oplus x_{\nu-2}.$$
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Hints: This exercise belongs to the chapter [[Theory_of_Stochastic_Signals/Two-Dimensional_Random_Variables|Two-Dimensional Random Variables]].
Hints:
*This exercise belongs to the chapter [[Theory_of_Stochastic_Signals/Two-Dimensional_Random_Variables|Two-Dimensional Random Variables]].
*Use the following table for moment calculation.
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This fact is shown again in the following table:
[[File:P_ID254__Sto_A_4_3Tab.png|left|frame|Table for moment calculation]]
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===Questions===
===Questions===
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{Determine the joint PDF $f_{xm}(x_\nu, m_\nu)$. Based on the result, evaluate the following statements (true or not).
{Determine the 2D–PDF $f_{xm}(x_\nu, m_\nu)$. Based on the result, evaluate the following statements.
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- The random variables $x_\nu$ and $m_\nu$ are statistically dependent.
- The random variables $x_\nu$ and $m_\nu$ are statistically dependent.
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{Determine the 2D PDF $f_{am}(a_\nu, m_\nu)$ and the correlation coefficient $\rho_{am}$. Which of the following statements are true?
{Determine the 2D–PDF $f_{am}(a_\nu, m_\nu)$ and the correlation coefficient $\rho_{am}$. Which of the following statements are true?
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+ The random variables $a_\nu$ and $m_\nu$ are statistically dependent.
+ The random variables $a_\nu$ and $m_\nu$ are statistically dependent.
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===Solution===
===Solution===
{{ML-Kopf}}
{{ML-Kopf}}
'''(1)''' It can be seen from the table on the information page that for the modulo 2 sum, the two values $0$ and $1$ have equal probability:
'''(1)''' It can be seen from the table in the information section that for the modulo–2 sum, the two values $0$ and $1$ have equal probability:
'''(2)''' The table shows that for each preassignment ⇒ $( x_{\nu-1}, x_{\nu-2}) = (0,0), (0,1), (1,0), (1,1)$ the values $m_\nu = 0$ respectively $m_\nu = 1$ are equally likely.
'''(2)''' The table shows that for each preassignment ⇒ $( x_{\nu-1}, x_{\nu-2}) = (0,0), (0,1), (1,0), (1,1)$, the values $m_\nu = 0$ and $m_\nu = 1$ resp. are equally likely.
'''(3)''' Correct are <u>the second and the last suggested solutions</u>.
'''(3)''' Correct are <u>the second and the last suggested solutions</u>.
*The 2D PDF consists of four Dirac functions, each with weight $1/4$.
*The 2D–PDF consists of four Dirac delta functions, each with weight $1/4$.
*One obtains this result, for example, by evaluating the table on the data page.
*One obtains this result, for example, by evaluating the table in the data section.
*Since $f_{xm}(x_\nu, m_\nu)$ is equal to the product $f_{x}(x_\nu) \cdot f_{m}(m_\nu)$ the quantities $x_\nu$ and $m_\nu$ are statistically independent.
*Since $f_{xm}(x_\nu, m_\nu)=f_{x}(x_\nu) \cdot f_{m}(m_\nu)$, the quantities $x_\nu$ and $m_\nu$ are statistically independent.
*Statistically independent random variables, however, are also linearly statistically independent, so they are certainly uncorrelated.
*Statistically independent random variables, however, are also linearly statistically independent, so they are certainly uncorrelated.
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'''(4)''' Within the sequence $\langle a_\nu \rangle$ of algebraic sum there are statistical bindings ⇒ <u>Answer 2</u>.
'''(4)''' Within the sequence $\langle a_\nu \rangle$ of algebraic sum there are statistical bindings ⇒ <u>Answer 2</u>.
*You can see this because the unconditional probability $ {\rm Pr}( a_{\nu} = 0) =1/8$ is,
*You can see this because the unconditional probability is $ {\rm Pr}( a_{\nu} = 0) =1/8$,
Algebraic & modulo–2 sumTable for moment calculation
A "clocked" random number generator returns a sequence $\langle x_\nu \rangle$ of binary random numbers.
It is assumed that the binary numbers $0$ and $1$ occur with equal probabilities and that the individual random numbers do not depend on each other.
The random numbers $ x_\nu \in \{0, 1\}$ are entered into the first memory location of a shift register and shifted down one digit with each clock pulse.
Two new random sequences $\langle a_\nu \rangle$ and $\langle m_\nu \rangle$ are formed from the contents of the three-digit shift register. Here denotes:
(2) The table shows that for each preassignment ⇒ $( x_{\nu-1}, x_{\nu-2}) = (0,0), (0,1), (1,0), (1,1)$, the values $m_\nu = 0$ and $m_\nu = 1$ resp. are equally likely.