Difference between revisions of "Aufgaben:Testbereich"

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[http://en.lntwww.de/Modulationsverfahren/Spreizfolgen_f%C3%BCr_CDMA#PN.E2.80.93Folgen_maximaler_L.C3.A4nge_.282.29 Oktalkennung (31)]
 
  
[[Modulationsverfahren/Spreizfolgen_f%C3%BCr_CDMA#PN.E2.80.93Folgen_maximaler_L.C3.A4nge_.282.29 |Oktalkennung (31)]]
+
:$$ \begin{array}{c}
 +
{\rm Operationen } \\
 +
{\rm modulo}\hspace{0.15cm}{\it q} = 4\\
 +
\end{array}\hspace{0.25cm} \Rightarrow\hspace{0.25cm}\text{Addition:      }
 +
\left[ \begin{array}{c|cccccc} + & 0 & 1 &2 & 3 \\ \hline
 +
                                                          0 & 0 & 1 &2 & 3 \\
 +
                                                          1 & 1 & 2 &3 & 0  \\
 +
                                                          2 & 2 & 3 &0 & 1 \\
 +
                                                          3 & 3 & 0 &1 & 2
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\end{array} \right] \hspace{-0.1cm} ,\hspace{0.25cm}\text{Multiplikation:      }
 +
\left[ \begin{array}{c|cccccc} \cdot & 0 & 1 &2 & 3 \\ \hline
 +
                                                          0 & 0 & 0 & 0 & 0  \\
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                                          1 & 0 & 1 & 2 & 3 \\
 +
                                          2 & 0 & 2 & 0 & 2 \\
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                                          3 & 0 & 3 & 2 & 1  \\
 +
\end{array} \right] .
 +
$$
  
  
 
+
$$\begin{tabular}{c}
[[Category:Aufgaben zu Beispiele von Nachrichtensystemen|^1.1 Allgemeine Beschreibung von ISDN^]]
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{\rm Operationen } \\
 +
{\rm modulo}\hspace{0.15cm}{\it q} = 4\\
 +
\end{tabular}\hspace{0.25cm} \Rightarrow\hspace{0.25cm}
 +
\begin{tabular}{c|cccccc}
 +
+ & 0 & 1 & 2 & 3  \\\hline
 +
0 & 0 & 1 & 2 & 3 \\
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1 & 1 & 2 & 3 & 0 \\
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2 & 2 & 3 & 0 & 1 \\
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3 & 3 & 0 & 1 & 2 \\
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\end{tabular}
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&\hspace{0.25cm}
 +
\begin{tabular}{c|cccccc}
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$\cdot$
 +
& 0 & 1 & 2 & 3 \\\hline
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0 & 0 & 0 & 0 & 0  \\
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1 & 0 & 1 & 2 & 3 \\
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2 & 0 & 2 & 0 & 2 \\
 +
3 & 0 & 3 & 2 & 1  \\
 +
\end{tabular}
 +
\hspace{0.05cm}.
 +
$$

Latest revision as of 09:18, 19 December 2017


$$ \begin{array}{c} {\rm Operationen } \\ {\rm modulo}\hspace{0.15cm}{\it q} = 4\\ \end{array}\hspace{0.25cm} \Rightarrow\hspace{0.25cm}\text{Addition: } \left[ \begin{array}{c|cccccc} + & 0 & 1 &2 & 3 \\ \hline 0 & 0 & 1 &2 & 3 \\ 1 & 1 & 2 &3 & 0 \\ 2 & 2 & 3 &0 & 1 \\ 3 & 3 & 0 &1 & 2 \end{array} \right] \hspace{-0.1cm} ,\hspace{0.25cm}\text{Multiplikation: } \left[ \begin{array}{c|cccccc} \cdot & 0 & 1 &2 & 3 \\ \hline 0 & 0 & 0 & 0 & 0 \\ 1 & 0 & 1 & 2 & 3 \\ 2 & 0 & 2 & 0 & 2 \\ 3 & 0 & 3 & 2 & 1 \\ \end{array} \right] . $$


$$\begin{tabular}{c} {\rm Operationen } \\ {\rm modulo}\hspace{0.15cm}{\it q} = 4\\ \end{tabular}\hspace{0.25cm} \Rightarrow\hspace{0.25cm} \begin{tabular}{c|cccccc} + & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 1 & 2 & 3 \\ 1 & 1 & 2 & 3 & 0 \\ 2 & 2 & 3 & 0 & 1 \\ 3 & 3 & 0 & 1 & 2 \\ \end{tabular} &\hspace{0.25cm} \begin{tabular}{c|cccccc} $\cdot$ & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 0 & 0 & 0 \\ 1 & 0 & 1 & 2 & 3 \\ 2 & 0 & 2 & 0 & 2 \\ 3 & 0 & 3 & 2 & 1 \\ \end{tabular} \hspace{0.05cm}. $$