Aufgaben:Testbereich: Difference between revisions

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[http://en.lntwww.de/Modulationsverfahren/Spreizfolgen_f%C3%BCr_CDMA#PN.E2.80.93Folgen_maximaler_L.C3.A4nge_.282.29 Oktalkennung (31)]
:$$ \left[ \begin{array}{cccc} + & 0 & 1 &2 & 3 \\ \hline
                                                          0 & 0 & 1 &2 & 3 \\
                                                          1 & 1 & 2 &3 & 0  \\
                                                          2 & 2 & 3 &0 & 1 \\
                                                          3 & 3 & 0 &1 & 2
\end{array} \right] .$$


[[Modulationsverfahren/Spreizfolgen_f%C3%BCr_CDMA#PN.E2.80.93Folgen_maximaler_L.C3.A4nge_.282.29 |Oktalkennung (31)]]
$${\mathbf{R}} =\left[ R_{ij} \right] = \left[ \begin{array}{cccc}R_{11} & R_{12} & \cdots & R_{1N} \\ R_{21} & R_{22}& \cdots & R_{2N} \\ \cdots & \cdots & \cdots &\cdots \\ R_{N1} & R_{N2} & \cdots & R_{NN}  \end{array} \right] .$$
 
$$\begin{tabular}{c}
+ & 0 & 1 & 2 & 3  \\\hline
0 & 0 & 1 & 2 & 3 \\
1 & 1 & 2 & 3 & 0 \\
2 & 2 & 3 & 0 & 1 \\
3 & 3 & 0 & 1 & 2 \\
\end{tabular}$$
$$\begin{tabular}{c|cccccc}
+ & 0 & 1 & 2 & 3  \\\hline
0 & 0 & 1 & 2 & 3 \\
1 & 1 & 2 & 3 & 0 \\
2 & 2 & 3 & 0 & 1 \\
3 & 3 & 0 & 1 & 2 \\
\end{tabular}$$
 
$$\begin{tabular}{c}
{\rm Operationen } \\
{\rm modulo}\hspace{0.15cm}{\it q} = 4\\
\end{tabular}\hspace{0.25cm} \Rightarrow\hspace{0.25cm}
\begin{tabular}{c|cccccc}
+ & 0 & 1 & 2 & 3  \\\hline
0 & 0 & 1 & 2 & 3 \\
1 & 1 & 2 & 3 & 0 \\
2 & 2 & 3 & 0 & 1 \\
3 & 3 & 0 & 1 & 2 \\
\end{tabular}
&\hspace{0.25cm}
\begin{tabular}{c|cccccc}
$\cdot$
& 0 & 1 & 2 & 3 \\\hline
0 & 0 & 0 & 0 & 0  \\
1 & 0 & 1 & 2 & 3 \\
2 & 0 & 2 & 0 & 2 \\
3 & 0 & 3 & 2 & 1  \\
\end{tabular}
\hspace{0.05cm}.  
$$






[[Category:Aufgaben zu Beispiele von Nachrichtensystemen|^1.1 Allgemeine Beschreibung von ISDN^]]
[[Category:Aufgaben zu Beispiele von Nachrichtensystemen|^1.1 Allgemeine Beschreibung von ISDN^]]

Revision as of 10:22, 16 August 2017

$$ \left[ \begin{array}{cccc} + & 0 & 1 &2 & 3 \\ \hline
                                                         0 & 0 & 1 &2 & 3 \\ 
                                                         1 & 1 & 2 &3 & 0  \\ 
                                                         2 & 2 & 3 &0 & 1 \\ 
                                                         3 & 3 & 0 &1 & 2

\end{array} \right] .$$

$${\mathbf{R}} =\left[ R_{ij} \right] = \left[ \begin{array}{cccc}R_{11} & R_{12} & \cdots & R_{1N} \\ R_{21} & R_{22}& \cdots & R_{2N} \\ \cdots & \cdots & \cdots &\cdots \\ R_{N1} & R_{N2} & \cdots & R_{NN} \end{array} \right] .$$

$$\begin{tabular}{c} + & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 1 & 2 & 3 \\ 1 & 1 & 2 & 3 & 0 \\ 2 & 2 & 3 & 0 & 1 \\ 3 & 3 & 0 & 1 & 2 \\ \end{tabular}$$ $$\begin{tabular}{c|cccccc} + & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 1 & 2 & 3 \\ 1 & 1 & 2 & 3 & 0 \\ 2 & 2 & 3 & 0 & 1 \\ 3 & 3 & 0 & 1 & 2 \\ \end{tabular}$$

$$\begin{tabular}{c} {\rm Operationen } \\ {\rm modulo}\hspace{0.15cm}{\it q} = 4\\ \end{tabular}\hspace{0.25cm} \Rightarrow\hspace{0.25cm} \begin{tabular}{c|cccccc} + & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 1 & 2 & 3 \\ 1 & 1 & 2 & 3 & 0 \\ 2 & 2 & 3 & 0 & 1 \\ 3 & 3 & 0 & 1 & 2 \\ \end{tabular} &\hspace{0.25cm} \begin{tabular}{c|cccccc} $\cdot$ & 0 & 1 & 2 & 3 \\\hline 0 & 0 & 0 & 0 & 0 \\ 1 & 0 & 1 & 2 & 3 \\ 2 & 0 & 2 & 0 & 2 \\ 3 & 0 & 3 & 2 & 1 \\ \end{tabular} \hspace{0.05cm}. $$