Aufgaben:Exercise 1.1: Music Signals: Difference between revisions
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{{quiz-Header|Buchseite=Signaldarstellung/Prinzip der Nachrichtenübertragung}} | {{quiz-Header|Buchseite=Signaldarstellung/Prinzip der Nachrichtenübertragung}} | ||
[[File:P_ID339__Sig_A_1_1.png|right|frame| | [[File:P_ID339__Sig_A_1_1.png|right|frame|Music signals, original and <br> noisy and/or distorted?]] | ||
On the right you see a ca. $\text{30 ms}$ long section of a music signal <math>q(t)</math>. It is the piece „For Elise” by Ludwig van Beethoven. | |||
* | *Underneath are drawn two sink signals <math>v_1(t)</math> and <math>v_2(t)</math>, which were recorded after the transmission of the music signal <math>q(t)</math> over two different channels. | ||
* | *The following controls allow you to listen to the first fourteen seconds of each of the three audio signals <math>q(t)</math>, <math>v_1(t)</math> and <math>v_2(t)</math>. | ||
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'' | ''Notes:'' | ||
* | *The task belongs to chapter [[Signal_Representation/Prinzip_der_Nachrichtenübertragung|Prinzip der Nachrichtenübertragung]]. | ||
=== | ===Questions=== | ||
<quiz display=simple> | <quiz display=simple> | ||
{ | {Estimate the signal frequency of <math>q(t)</math> in the displayed section. | ||
|type="()"} | |type="()"} | ||
- | - The signal frequency is approximately <math>f = 250\,\text{Hz}</math>. | ||
+ | + The signal frequency is approximately <math>f = 500\,\text{Hz}</math>. | ||
- | - The signal frequency is about <math>f = 1\,\text{kHz}</math>. | ||
{ | {Which statements are true for the signal <math>v_1(t)</math> ? | ||
|type="[]"} | |type="[]"} | ||
+ | + The signal <math>v_1(t)</math> is undistorted compared to <math>q(t)</math>. | ||
- | - The signal <math>v_1(t)</math> shows distortions compared to <math>q(t)</math> . | ||
- | - The signal <math>v_1(t)</math> is noisy compared to <math>q(t)</math> . | ||
{ | {Which statements are true for the signal <math>v_2(t)</math> ? | ||
|type="[]"} | |type="[]"} | ||
+ | + The signal <math>v_2(t)</math> is undistorted compared to <math>q(t)</math> . | ||
- | - The signal <math>v_2(t)</math> shows distortions compared to <math>q(t)</math> . | ||
+ | + The signal <math>v_2(t)</math> is noisy compared to <math>q(t)</math> . | ||
{ | {One of the signals is opposite the original <math>q(t)</math> undistorted and not noisy. <br> Estimate the attenuation factor and the running time for this. | ||
|type="{}"} | |type="{}"} | ||
<math> \alpha \ = \ </math> { 0.2-0.4 } | <math> \alpha \ = \ </math> { 0.2-0.4 } | ||
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</quiz> | </quiz> | ||
=== | ===Solutions=== | ||
{{ML-Kopf}} | {{ML-Kopf}} | ||
'''(1)''' | '''(1)''' Correct is the <u>solution 2</u>: | ||
* | *In the marked range of $20$ milliseconds approx. $10$ oscillations can be detected. | ||
* | *From this the result follows approximately for the signal frequency; $f = {10}/(20 \,\text{ms}) = 500 \,\text{Hz}$. | ||
'''(2)''' | '''(2)''' Correct is the <u>solution 1</u>: | ||
* | *The signal <math>v_1(t)</math> is undistorted compared to the original signal <math>q(t)</math>. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$ | ||
*Eine Dämpfung <math>\alpha</math> und eine Laufzeit <math>\tau</math> führen nicht zu Verzerrungen, sondern das Signal ist dann nur leiser und es kommt später als das Original. | *Eine Dämpfung <math>\alpha</math> und eine Laufzeit <math>\tau</math> führen nicht zu Verzerrungen, sondern das Signal ist dann nur leiser und es kommt später als das Original. | ||
Revision as of 23:15, 7 August 2020

noisy and/or distorted?
On the right you see a ca. $\text{30 ms}$ long section of a music signal [math]\displaystyle{ q(t) }[/math]. It is the piece „For Elise” by Ludwig van Beethoven.
- Underneath are drawn two sink signals [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math], which were recorded after the transmission of the music signal [math]\displaystyle{ q(t) }[/math] over two different channels.
- The following controls allow you to listen to the first fourteen seconds of each of the three audio signals [math]\displaystyle{ q(t) }[/math], [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math].
Originalsignal [math]\displaystyle{ q(t) }[/math]
Sinkensignal [math]\displaystyle{ v_1(t) }[/math]
Sinkensignal [math]\displaystyle{ v_2(t) }[/math]
Notes:
- The task belongs to chapter Prinzip der Nachrichtenübertragung.
Questions
Solutions
(1) Correct is the solution 2:
- In the marked range of $20$ milliseconds approx. $10$ oscillations can be detected.
- From this the result follows approximately for the signal frequency; $f = {10}/(20 \,\text{ms}) = 500 \,\text{Hz}$.
(2) Correct is the solution 1:
- The signal [math]\displaystyle{ v_1(t) }[/math] is undistorted compared to the original signal [math]\displaystyle{ q(t) }[/math]. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$
- Eine Dämpfung [math]\displaystyle{ \alpha }[/math] und eine Laufzeit [math]\displaystyle{ \tau }[/math] führen nicht zu Verzerrungen, sondern das Signal ist dann nur leiser und es kommt später als das Original.
(3) Richtig sind die Lösungsvorschläge 1 und 3:
- Man erkennt sowohl im dargestellten Signalverlauf [math]\displaystyle{ v_2(t) }[/math] als auch im Audiosignal additives Rauschen ⇒ Lösungsvorschlag 3.
- Der Signalrauschabstand beträgt dabei ca. $\text{30 dB}$; dies ist aber aus dieser Darstellung nicht erkennbar.
- Richtig ist aber auch der Lösungsvorschlag 1: Ohne diesen Rauschanteil wäre [math]\displaystyle{ v_2(t) }[/math] identisch mit [math]\displaystyle{ q(t) }[/math].
(4) Das Signal [math]\displaystyle{ v_1(t) }[/math] ist formgleich mit dem Originalsignal [math]\displaystyle{ q(t) }[/math] und unterscheidet sich von diesem lediglich
- durch den Amplitudenfaktor $\alpha = \underline{\text{0.3}}$ (dies entspricht etwa $\text{–10 dB)}$
- und die Laufzeit $\tau = \underline{10\,\text{ms}}$.