Difference between revisions of "Aufgaben:Exercise 3.8: OVSF Codes"
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| − | '''(3)''' If three users are supplied with $J = 4$, only two | + | '''(3)''' If three users are supplied with $J = 4$, only two users can be served by a spreading sequence with $J = 8$ (see example yellow background in the graphic) $\ \Rightarrow \ \ \underline{K = 5}$. |
Revision as of 14:59, 8 July 2020
a OVSF–Code
The spreading codes for UMTS should
- be orthogonal, in order to avoid mutual influence of the participants,
- at the same time also allow a flexible realization of different spreading factors $J$ .
An example are the orthogonal Variable Spreading Factor (OVSF),which provide the spreading codes of lengths from $J = 4$ to $J = 512$ .
As shown in the graphic, these can be created with the help of a code tree. In doing so, each branching from a code $\mathcal{C}$ results in two new codes $(+\mathcal{C}\ +\mathcal{C})$ und $(+\mathcal{C} \ –\mathcal{C})$.
The diagram illustrates the principle given here using the following example $J = 4$. If you number the spreading sequences from $0$ to $J –1$ through, the spreading sequences result
- $$\langle c_\nu^{(0)}\rangle = \ {+\hspace{-0.05cm}1}\hspace{0.15cm} {+\hspace{-0.05cm}1} \hspace{0.15cm} {+\hspace{-0.05cm}1}\hspace{0.15cm} {+\hspace{-0.05cm}1} \hspace{0.05cm},$$
- $$ \langle c_\nu^{(1)}\rangle = {+\hspace{-0.05cm}1}\hspace{0.15cm} {+\hspace{-0.05cm}1} \hspace{0.15cm} {-\hspace{-0.05cm}1}\hspace{0.15cm} {-\hspace{-0.05cm}1} \hspace{0.05cm},$$
- $$\langle c_\nu^{(2)}\rangle = \ {+\hspace{-0.05cm}1}\hspace{0.15cm} {-\hspace{-0.05cm}1} \hspace{0.15cm} {+\hspace{-0.05cm}1}\hspace{0.15cm} {-\hspace{-0.05cm}1} \hspace{0.05cm},$$
- $$ \langle c_\nu^{(3)}\rangle = {+\hspace{-0.05cm}1}\hspace{0.15cm} {-\hspace{-0.05cm}1} \hspace{0.15cm} {-\hspace{-0.05cm}1}\hspace{0.15cm} {+\hspace{-0.05cm}1} \hspace{0.05cm}.$$
According to this nomenclature, for the spreading factor $J = 8$ there are the spreading sequences $\langle c_\nu^{(0)}\rangle, \text{...} ,\langle c_\nu^{(7)}\rangle.$
It should be noted that no predecessor or successor of a code may be used by other participants.
- In the example, four spreading codes with spreading factor $J = 4$ could be used, or
- the three codes highlighted in yellow - once with $J = 2$ and twice with $J = 4$.
Notes:
- This task belongs to the chapter Spreizfolgen für CDMA.
- Particular reference is made to the page Codes mit variablem Spreizfaktor (OVSF–Code).
Fragebogen
Musterlösung
(1) The following graphic shows the OVSF tree structure for $J = $8 users.
- From this it can be seen that the solutions 1, 3 and 4 apply, but not the second.
(2) If each user is assigned a spreading code with the spreading degree $J = 8$, $K_{\rm max} \ \underline{= 8}$ users can be supplied.
(3) If three users are supplied with $J = 4$, only two users can be served by a spreading sequence with $J = 8$ (see example yellow background in the graphic) $\ \Rightarrow \ \ \underline{K = 5}$.
(4) We denote
- $K_{4} = 2$ as the number of spreading sequences with $J = 4$,
- $K_{8} = 1$ as the number of spreading sequences with $J = 8$,
- $K_{16} = 2$as the number of spreading sequences with $J = 16$,
- $K_{32} = 8$as the number of spreading sequences with $J = 32$,
Then the following condition must be fulfilled:
- $$K_4 \cdot \frac{32}{4} + K_8 \cdot \frac{32}{8} +K_{16} \cdot \frac{32}{16} +K_{32} \cdot \frac{32}{32} \le 32\hspace{0.3cm} \Rightarrow \hspace{0.3cm} K_4 \cdot8 + K_8 \cdot 4 +K_{16} \cdot 2 +K_{32} \cdot1 \le 32 \hspace{0.05cm}.$$
- Because $2 \cdot 8 + 1 \cdot 4 + 2 \cdot 2 + 8 = 32$ the desired assignment is just allowed ⇒ The answer is YES.
- For example, providing the $J = 4$ twice blocks the upper half of the tree, after providing a $J = 8$ spreading code, $3$ of the $8$ branches remain to be occupied at the $J = 8$ level, and so on and so forth.
