Aufgaben:Exercise 1.1: Music Signals: Difference between revisions
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{{quiz-Header|Buchseite=Signaldarstellung/Prinzip der Nachrichtenübertragung}} | {{quiz-Header|Buchseite=Signaldarstellung/Prinzip der Nachrichtenübertragung}} | ||
[[File:P_ID339__Sig_A_1_1.png|right|frame|Music signals, original | [[File:P_ID339__Sig_A_1_1.png|right|frame|Music signals, original, <br> noisy and/or distorted?]] | ||
On the right you see a ca. $\text{30 ms}$ long section of a music signal <math>q(t)</math>. It is the piece „For Elise” by Ludwig van Beethoven. | On the right you see a ca. $\text{30 ms}$ long section of a music signal <math>q(t)</math>. It is the piece „For Elise” by Ludwig van Beethoven. | ||
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*The signal <math>v_1(t)</math> is undistorted compared to the original signal <math>q(t)</math>. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$ | *The signal <math>v_1(t)</math> is undistorted compared to the original signal <math>q(t)</math>. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$ | ||
* | *An attenuation <math>\alpha</math> and a delay <math>\tau</math> do not cause distortion, but the signal is then only quieter and comes later than the original. | ||
'''(3)''' | '''(3)''' Correct are the <u>solutions 1 and 3</u>: | ||
* | *One can recognize both in the displayed signal <math>v_2(t)</math> and in the audio signal ''additive noise'' ⇒ <u>solution 3</u>. | ||
* | *The signal-to-noise ratio is approx. $\text{30 dB}$; but this cannot be seen from this representation. | ||
* | *Correct is also the <u>solution 1</u>: Without this noise component <math>v_2(t)</math> identical with <math>q(t)</math>. | ||
'''(4)''' | '''(4)''' The signal <math>v_1(t)</math> is identical in form to the original signal <math>q(t)</math> and differs from it only | ||
* | *by the attenuation factor $\alpha = \underline{\text{0.3}}$ (dies entspricht etwa $\text{–10 dB)}$ | ||
* | *and the delay $\tau = \underline{10\,\text{ms}}$. | ||
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[[Category:Aufgaben zu Signaldarstellung|^1. Grundbegriffe der Nachrichtentechnik^]] | [[Category:Aufgaben zu Signaldarstellung|^1. Grundbegriffe der Nachrichtentechnik^]] | ||
Revision as of 14:15, 8 August 2020

noisy and/or distorted?
On the right you see a ca. $\text{30 ms}$ long section of a music signal [math]\displaystyle{ q(t) }[/math]. It is the piece „For Elise” by Ludwig van Beethoven.
- Underneath are drawn two sink signals [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math], which were recorded after the transmission of the music signal [math]\displaystyle{ q(t) }[/math] over two different channels.
- The following controls allow you to listen to the first fourteen seconds of each of the three audio signals [math]\displaystyle{ q(t) }[/math], [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math].
Originalsignal [math]\displaystyle{ q(t) }[/math]
Sinkensignal [math]\displaystyle{ v_1(t) }[/math]
Sinkensignal [math]\displaystyle{ v_2(t) }[/math]
Notes:
- The task belongs to chapter Prinzip der Nachrichtenübertragung.
Questions
Solutions
(1) Correct is the solution 2:
- In the marked range of $20$ milliseconds approx. $10$ oscillations can be detected.
- From this the result follows approximately for the signal frequency; $f = {10}/(20 \,\text{ms}) = 500 \,\text{Hz}$.
(2) Correct is the solution 1:
- The signal [math]\displaystyle{ v_1(t) }[/math] is undistorted compared to the original signal [math]\displaystyle{ q(t) }[/math]. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$
- An attenuation [math]\displaystyle{ \alpha }[/math] and a delay [math]\displaystyle{ \tau }[/math] do not cause distortion, but the signal is then only quieter and comes later than the original.
(3) Correct are the solutions 1 and 3:
- One can recognize both in the displayed signal [math]\displaystyle{ v_2(t) }[/math] and in the audio signal additive noise ⇒ solution 3.
- The signal-to-noise ratio is approx. $\text{30 dB}$; but this cannot be seen from this representation.
- Correct is also the solution 1: Without this noise component [math]\displaystyle{ v_2(t) }[/math] identical with [math]\displaystyle{ q(t) }[/math].
(4) The signal [math]\displaystyle{ v_1(t) }[/math] is identical in form to the original signal [math]\displaystyle{ q(t) }[/math] and differs from it only
- by the attenuation factor $\alpha = \underline{\text{0.3}}$ (dies entspricht etwa $\text{–10 dB)}$
- and the delay $\tau = \underline{10\,\text{ms}}$.