Difference between revisions of "Aufgaben:Exercise 4.1Z: Appointment to Breakfast"

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[[File:P_ID245__Sto_Z_4_1.jpg|right|frame|Candidates for Chancellor having breakfast in 2002]]
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[[File:P_ID245__Sto_Z_4_1.jpg|right|frame|Chancellor candidates – breakfast in 2002]]
 
Ms. M. and Mr. S. are known to meet often for a joint breakfast:  
 
Ms. M. and Mr. S. are known to meet often for a joint breakfast:  
 
*Both promise to come to such a meeting on a certain day between 8 am and 9 am.  
 
*Both promise to come to such a meeting on a certain day between 8 am and 9 am.  
*Further, they agree that each of them will arrive in this period (and only in this period) on "good luck" and wait up to fifteen minutes for the other.
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*Further,&nbsp; they agree that each of them will arrive in this period&nbsp; (and only in this period)&nbsp; on&nbsp; "good luck"&nbsp; <br>and wait up to fifteen minutes for the other.
 
 
 
 
 
 
 
 
  
  
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Hints:
 
Hints:
*The task belongs to the chapter&nbsp; [[Theory_of_Stochastic_Signals/Two-Dimensional_Random_Variables|Two-Dimensional Random Variables]].
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*The exercise belongs to the chapter&nbsp; [[Theory_of_Stochastic_Signals/Two-Dimensional_Random_Variables|Two-Dimensional Random Variables]].
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*Use the minute of arrival time as the time in the following questions:&nbsp; <br>"Minute = 0"&nbsp; stands for 8 o'clock, "Minute = 60"&nbsp; for 9 o'clock.
*Use the minute of arrival time as the time in the following questions:&nbsp; <br>"Minute = 0" stands for 8 o'clock, "Minute = 60" for 9 o'clock.
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*The exercise arose before the 2002 German Bundestag elections,&nbsp; when both Dr. Angela Merkel and Dr. Edmund Stoiber wanted to become the CDU/CSU's candidate for chancellor.  
*The task arose before the 2002 Bundestag elections, when both Dr. Angela Merkel and Dr. Edmund Stoiber wanted to become the CDU/CSU's candidate for chancellor.  
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*At a joint breakfast in Wolfratshausen,&nbsp; Ms. Merkel renounced.&nbsp; The later election was won by Gerhard Schröder&nbsp; (SPD).
*At a joint breakfast in Wolfratshausen, Ms. Merkel renounced.&nbsp; The later election was won by Gerhard Schröder (SPD).
 
  
  
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<quiz display=simple>
 
<quiz display=simple>
{What is the probability $p_1$ that the two will meet when Mr. S. arrives at 8:30? Give reasons for your answer.
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{What is the probability&nbsp; $p_1$&nbsp; that the two will meet when Mr. S. arrives at 8:30?&nbsp; Give reasons for your answer.
 
|type="{}"}
 
|type="{}"}
 
$p_1 \ = \ $ { 50 1% } $\ \%$
 
$p_1 \ = \ $ { 50 1% } $\ \%$
  
  
{Which arrival time should Ms. M. choose if she does not actually want to meet Mr. S., but still wants to keep to the agreement made? <br>What is the probability $p_2$ that Ms. M. and Mr. S. will meet?
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{Which arrival time should Ms. M. choose if she does not actually want to meet Mr. S.,&nbsp; but still wants to keep to the agreement made? <br>What is the probability&nbsp; $p_2$&nbsp; that Ms. M. and Mr. S. will meet?
 
|type="{}"}
 
|type="{}"}
 
$p_2 \ = \ $ { 25 1% } $\ \%$
 
$p_2 \ = \ $ { 25 1% } $\ \%$
  
  
{Which arrival time should Ms. M. choose if she not only wants to avoid a meeting as much as possible, but also wants to minimize the waiting time?
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{Which arrival time should Ms. M. choose if she not only wants to avoid a meeting as much as possible,&nbsp; but also wants to minimize the waiting time?
 
|type="{}"}
 
|type="{}"}
 
$\rm minute \ = \ ${ 60 }
 
$\rm minute \ = \ ${ 60 }
  
  
{What is the probability&nbsp; $p_4$&nbsp; for a meeting in general, that is, if both actually appear on "Gut Gl&uuml;ck"?
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{What is the probability&nbsp; $p_4$&nbsp; for a meeting in general,&nbsp; that is,&nbsp; if both actually appear on "good luck"?
 
|type="{}"}
 
|type="{}"}
 
$p_4 \ = \ $ { 43.75 1% } $\ \%$
 
$p_4 \ = \ $ { 43.75 1% } $\ \%$

Revision as of 13:10, 7 February 2022

Chancellor candidates – breakfast in 2002

Ms. M. and Mr. S. are known to meet often for a joint breakfast:

  • Both promise to come to such a meeting on a certain day between 8 am and 9 am.
  • Further,  they agree that each of them will arrive in this period  (and only in this period)  on  "good luck" 
    and wait up to fifteen minutes for the other.



Hints:

  • The exercise belongs to the chapter  Two-Dimensional Random Variables.
  • Use the minute of arrival time as the time in the following questions: 
    "Minute = 0"  stands for 8 o'clock, "Minute = 60"  for 9 o'clock.
  • The exercise arose before the 2002 German Bundestag elections,  when both Dr. Angela Merkel and Dr. Edmund Stoiber wanted to become the CDU/CSU's candidate for chancellor.
  • At a joint breakfast in Wolfratshausen,  Ms. Merkel renounced.  The later election was won by Gerhard Schröder  (SPD).


Questions

1

What is the probability  $p_1$  that the two will meet when Mr. S. arrives at 8:30?  Give reasons for your answer.

$p_1 \ = \ $

$\ \%$

2

Which arrival time should Ms. M. choose if she does not actually want to meet Mr. S.,  but still wants to keep to the agreement made?
What is the probability  $p_2$  that Ms. M. and Mr. S. will meet?

$p_2 \ = \ $

$\ \%$

3

Which arrival time should Ms. M. choose if she not only wants to avoid a meeting as much as possible,  but also wants to minimize the waiting time?

$\rm minute \ = \ $

4

What is the probability  $p_4$  for a meeting in general,  that is,  if both actually appear on "good luck"?

$p_4 \ = \ $

$\ \%$


Solution

(1)  If Mr. S. arrives at 8:30, he will meet Ms. M. if she arrives between 8:15 and 8:45. Thus the probability

$$p_1 = \text{Pr(Mr. S. meets Ms. M.)}\hspace{0.15cm}\underline{=50\%}.$$


"Favorable area" for meeting

(2)  If Ms. M. arrives at 8 a.m., she meets Mr. S. only if he arrives before 8:15.

  • If Ms. M. arrives at 9 a.m., Mr. S. must arrive after 8:45 a.m. so that they can meet.
  • The probability of meeting is the same in both cases:
$$p_2 = \big[\text{Min Pr(Mr. S. meets Ms. M.)}\big]\hspace{0.15cm}\underline{=25\%}.$$


(3)  Of the two arrival times calculated in (2), 9 o'clock  $(\underline{\text{Minute = 60}})$  is more favorable,
      since she – if Mr. S. is not there – can leave immediately.


(4)  The probability  $p_4$  is given as the ratio of the red area in the graph to the total area  $1$.

  • Using the triangular areas, one obtains:
$$p_4=\rm 1-2\cdot\frac{1}{2}\cdot\frac{3}{4}\cdot\frac{3}{4}=\frac{7}{16}\hspace{0.15cm}\underline{=\rm 43.75\%}.$$