Exercise 1.4Z: Sum of Ternary Quantities
From LNTwww
Sum of two ternary variables $x$ and $y$
Let be given the ternary random variables
- $$x ∈ {–2, \ 0, +2},$$
- $$y ∈ {–1, \ 0, +1}.$$
- These two ternary values each occur with equal probability.
- From this, the sum $s = x + y$ is formed as a new random variable.
- The adjacent scheme shows that the sum $s$ can take all integer values between $–3$ and $+3$ :
- $$ s \in \{-3, -2, -1, \ 0, +1, +2, +3\}.$$
Hints:
- The exercise belongs to the chapter Statistical dependence and independence.
- The topic of this chapter is illustrated with examples in the (German language) learning video
- Statistische Abhängigkeit und Unabhängigkeit $\Rightarrow$ "Statistical dependence and independence".
Questions
Solution
Ternary variables in the Venn diagram
In the adjacent graph
- the three fields belonging to the event $„x > 0“$ are outlined in purple,
- the fields for $„s > 0“$ are highlighted in yellow.
All sought probabilities can be determined here with the help of the classical definition.
(1) This event is marked by the fields with yellow background:
- $$\rm Pr (\it s > \rm 0) = \rm 4/9 \hspace{0.15cm}\underline { \approx \rm 0.444}.$$
(2) The following facts hold here:
- $$\rm Pr \big[(\it x > \rm 0) \cap (\it s>\rm 0) \big ] = \rm Pr(\it x > \rm 0) =\rm 3/9\hspace{0.15cm}\underline { \approx \rm 0.333}. $$
(3) Using the results of subtasks (1) and (2) , it follows:
- $$\rm Pr \big[(\it x > \rm 0) \hspace{0.05cm}| \hspace{0.05cm} (\it s > \rm 0)\big] = \frac{{\rm Pr} [(\it x > \rm 0) \cap (\it s > \rm 0)]}{{\rm Pr}(\it s > \rm 0)}= \frac{3/9}{4/9}\hspace{0.15cm}\underline {= 0.75}.$$
(4) Analogous to subtask (3) now holds:
- $$\rm Pr(\it s > \rm 0 \hspace{0.05cm} | \hspace{0.05cm} \it x > \rm 0)=\frac{Pr \big[(\it x > \rm 0) \cap (\it s > \rm 0) \big]}{Pr(\it x >\rm 0)}=\rm \frac{3/9}{3/9}\hspace{0.15cm}\underline {= 1}.$$
