Difference between revisions of "Mobile Communications/Multi-Path Reception in Mobile Communications"
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*In addition, it must be taken into account that the reflection from buildings or the ground leads to a phase rotation of $\pi \ (180^\circ)$. This causes the factor $k_2$ to become negative. In the following, however, the negative sign of $k_2$ is ignored.<br><br> | *In addition, it must be taken into account that the reflection from buildings or the ground leads to a phase rotation of $\pi \ (180^\circ)$. This causes the factor $k_2$ to become negative. In the following, however, the negative sign of $k_2$ is ignored.<br><br> | ||
− | <i>Note:</i> We refer here to the SWF applet [[Applets:Multipath propagation and frequency selectivity (Applet)| | + | <i>Note:</i> We refer here to the SWF applet [[Applets:Multipath propagation and frequency selectivity (Applet)|Multipath propagation and frequency selectivity]] '''(German language!)'''. |
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::<math>H(f) = {R(f)}/{S(f)} = 1 + k_0 \cdot {\rm e}^{ - {\rm j} \hspace{0.05cm}\cdot \hspace{0.05cm}2 \pi f \hspace{0.05cm} \cdot \hspace{0.05cm} \tau_0} \hspace{0.05cm}.</math> | ::<math>H(f) = {R(f)}/{S(f)} = 1 + k_0 \cdot {\rm e}^{ - {\rm j} \hspace{0.05cm}\cdot \hspace{0.05cm}2 \pi f \hspace{0.05cm} \cdot \hspace{0.05cm} \tau_0} \hspace{0.05cm}.</math> | ||
− | *Through the [[Signal_Representation/Fourier_Transform_and_Its_Inverse#The_Second_Fourier_Integral|Fourier | + | *Through the [[Signal_Representation/Fourier_Transform_and_Its_Inverse#The_Second_Fourier_Integral|inverse Fourier transform]] one obtains the impulse response |
::<math>h(\tau) = 1 + k_0 \cdot \delta(\tau - \tau_0) \hspace{0.05cm}.</math> | ::<math>h(\tau) = 1 + k_0 \cdot \delta(\tau - \tau_0) \hspace{0.05cm}.</math> |
Revision as of 13:21, 15 February 2021
Contents
Time-invariant description of the two-way channel
We assume the scenario shown in the graph. This assumes
- Transmitter and receiver are at rest:
Then both the channel transfer function and the impulse response are time–independent. For all times $t$ applies $H(f, \hspace{0.05cm}t) = H(f)$ and $h(\tau, \hspace{0.05cm}t) = h(\tau)$.
- A two-way channel:
The transmission signal $s(t)$ reaches the receiver on a direct path with the path length $d_1$, and there is also an echo due to the reflective ground $($the total path length is $d_2)$.
Thus, the following applies to the received signal:
- \[r(t) = r_1(t) + r_2(t) = k_1 \cdot s( t - \tau_1) + k_2 \cdot s( t - \tau_2) \hspace{0.05cm}.\]
The following statements should be noted:
- Compared to the transmission signal, the signal $r_1(t)$ received via the direct path is attenuated by the factor $k_1$ and delayed by $\tau_1$ .
- The attenuation factor $k_1$ is calculated with the path loss model. The greater the transmission frequency $f_{\rm S}$, the distance $d_1$ and the exponent $\gamma$ are, the smaller is $k_1$ and thus the greater is the loss.
- The delay $\tau_1 = d_1/c$ increases proportionally with the path length $d_1$ . For example, for the distance $d_1 = 3 \ \rm km$ and the speed of light $c = 3 \cdot 10^8 \ \rm m/s$ the delay will be $\tau_1 = 10 \ \rm µ s$.
- Because of the larger path length $(d_2 > d_1)$ the second path has a greater attenuation ⇒ smaller pre-factor ⇒ $(|k_2| < |k_1|)$ and accordingly also a greater delay $(\tau_2 > \tau_1)$.
- In addition, it must be taken into account that the reflection from buildings or the ground leads to a phase rotation of $\pi \ (180^\circ)$. This causes the factor $k_2$ to become negative. In the following, however, the negative sign of $k_2$ is ignored.
Note: We refer here to the SWF applet Multipath propagation and frequency selectivity (German language!).
Simple time–invariant model of the two-way channel
For the frequency selectivity
- the path loss $($marked by $k_1)$ and
- the basic term $\tau_1$
are irrelevant. The only decisive factors here are path loss differences and runtime differences.
We will now describe the two-way channel with the new parameters
- $$k_0 = |k_2 /k_1 |,\hspace{0.5cm} \tau_0 = \tau_2 - \tau_1.$$
This results in:
- \[r(t) = r_1(t) + k_0 \cdot r_1( t - \tau_0) \hspace{0.5cm}{\rm with} \hspace{0.5cm} r_1(t) = k_1 \cdot s( t - \tau_1)\hspace{0.05cm}.\]
The figure illustrates the equation. With the simplifications $k_1 = 1$ and $\tau_1 = 0$ ⇒ $r_1(t) = s(t)$ we obtain:
- \[r(t) = s(t) + k_0 \cdot s( t - \tau_0) \hspace{0.05cm}.\]
From this simplified model (without the grey-shaded block) important descriptive variables can be easily calculated:
- If you use the Shifting Theorem you get the transfer function
- \[H(f) = {R(f)}/{S(f)} = 1 + k_0 \cdot {\rm e}^{ - {\rm j} \hspace{0.05cm}\cdot \hspace{0.05cm}2 \pi f \hspace{0.05cm} \cdot \hspace{0.05cm} \tau_0} \hspace{0.05cm}.\]
- Through the inverse Fourier transform one obtains the impulse response
- \[h(\tau) = 1 + k_0 \cdot \delta(\tau - \tau_0) \hspace{0.05cm}.\]
$\text{Example 1:}$ We consider a two-way channel with delay $\tau_0 = 2 \ \ \rm µ s$ and some attenuation factors $k_0$ between $0$ and $1$.
The graph shows the transfer function in terms of its absolute value in the range $\pm 1 \ \rm MHz$. You can see from this representation:
- The transfer function $H(f)$ and also its absolute value is periodic with $1/\tau_0 = 500 \ \rm kHz$.
- This frequency period here is also the coherence bandwidth .
- The fluctuations around the mean value $\vert H(f) \vert = 1$ are the stronger, the larger the (relative) contribution $k_0$ of the second path is (i.e. the echo).
Coherence bandwidth as a function of M
We are now modifying the two-way model in such a way that we allow more than two paths, as is the case for mobile communications.
In general, the multipath channel model is thus:
- $$ r(t)= \sum_{m = 1}^{M}\hspace{0.15cm} k_m \cdot s( t - \tau_m)$$
- $$\Rightarrow \hspace{0.3cm} h(\tau) = \sum_{m = 1}^{M}\hspace{0.15cm} k_m \cdot \delta( \tau - \tau_m) \hspace{0.05cm}.$$
We now compare
- the two-way channel $(M = 2)$ with the parameters
- \[\tau_1 = 1\,\,{\rm µ s}\hspace{0.05cm}, \hspace{0.2cm} k_1 = 0.8\hspace{0.05cm}, \hspace{0.2cm} \tau_2 = 3\,\,{\rm µ s}\hspace{0.05cm}, \hspace{0.2cm} k_2 = 0.6\]
- and the following three-way channel $(M = 3)$:
- $$\tau_1 = 1\,\,{\rm µ s}\hspace{0.05cm}, \hspace{0.2cm} k_1 = 0.8\hspace{0.05cm}, \hspace{0.2cm} \tau_2 = 3\,\,{\rm µ s}\hspace{0.05cm}, \hspace{0.2cm} k_2 \approx 0.43\hspace{0.05cm}, \hspace{0.2cm} \tau_3 = 9\,\,{\rm µ s}\hspace{0.05cm}, \hspace{0.2cm} k_3 \approx 0.43 \hspace{0.05cm}.$$
With the selected constants, both channels have the root mean square value ${\rm E}\big [k_m^2\big ] = 1$ .
The graph shows the magnitude functions $ |H(f)|$ of both channels and the corresponding impulse responses $h(\tau)$. One can see from these graphs:
- In the blue channel $(M = 2)$ the Dirac functions occur in a range of width $\Delta \tau_{\rm max} = 2 \ \rm µ s$.
- With the red channel $(M = 3)$ this value is four times as large: $\Delta \tau_{\rm max} = 8 \ \rm µ s$.
- As a first approximation for coherence bandwidth $B_{\rm K}\hspace{0.01cm}'\approx 1/ \Delta \tau_{\rm max}$ is often used, which may differ from the correct value by a factor of $2$ or more.
- This simple approximation, marked with an apostrophe, results for the blue channel to $B_{\rm K}\hspace{0.01cm}'= 500 \ \rm kHz$.
- For the red channel it is $B_{\rm K}\hspace{0.01cm}'= 125 \ \rm kHz$ which is just one fourth of the blue channel's.
$\text{In general the following applies:} $
- If the signal bandwidth $B_{\rm S} = 1/T_{\rm S}$ is much smaller than the coherence bandwidth $B_{\rm K}$, then the channel can be considered as non-frequency selective
$(T_{\rm S}$ denotes the symbol duration$)$. - In other words: For a given $B_{\rm S}$ the smaller the coherence bandwidth $B_{\rm K}$ or the larger the maximum delay $\Delta \tau_{\rm max}$ the greater the frequency selectivity.
- This also means: The frequency selectivity is often determined by the longest echo.
- Many short echoes with a total energy $E$ are less disturbing than one long echo of the same energy $E$.
Consideration of the time variance
Up to now the attenuation factors $k_m$ were assumed to be constant. For mobile radio, however, this channel model is only correct if transmitter and receiver are static, which is merely a special case for this communication system.
For a moving user, these constant factors $k_m$ must be replaced by the time-variant factors $z_m(t)$ which are each based on random processes. You should note this:
- The magnitudes of the complex weighting factors $z_m(t)$ are Rayleigh distributed according to the page Exemplary signal curves with Rayleigh fading or – with line-of-sight connection – Rice distributed, as described in Exemplary signal curves with Rice fading .
- The bindings within the process $z_m(t)$ are related to the mobility properties (speed, direction, etc.) to the Jakes Spectrum .
The figure shows the generally valid model for the mobile communications channel. "Generally valid" but only with reservations, as explained at the end of $\text{Example 2}$.
For an understanding of the figure we refer to the chapter General description of the mobile communications channel. Please note:
- The $M$ main paths are characterized by large propagation time differences.
- The time-variant complex coefficients $z_m(t)$ result from the sum of many secondary paths whose delay times are all approximately the same $\tau_m$ .
$\text{Example 2:}$ Studies have shown that in mobile communications no more than four or five main pathways are effective at the same time.
The represented 2D–impulse response $h(\tau,\hspace{0.1cm} t)$ applies to $M = 3$ main paths with time-variant behavior, where the received power decreases with increasing delay in the statistical average. For this graph the above sketched channel model is used as a basis.
Two different views are shown:
- The left image shows $h(\tau,\hspace{0.1cm} t)$ as a function of the delay time $\tau$ at a fixed time $t$.
- The viewing direction in the right image is rotated by $90^\circ$ . By using the color coding, the representation should be understandable.
This geaphic also shows the weak point of our mobile communications channel model: Although the coefficients $z_m(t)$ are variable, the delay times $\tau_m$ are fixed. This does not correspond to reality, if the mobile station is moving and the connection takes place in a changing environment. $\tau_m(t)$ should be considered.
$\text{Conclusion:}$ It is helpful to make a slight modification to the above model:
- One chooses the number $M'$ of (possible) main paths much larger than necessary and sets $\tau_m = m \cdot \Delta \tau$.
- The incremental (minimum resolvable) delay $\Delta \tau = T_{\rm S}$ results from the sampling rate and thus from the bandwidth $B_{\rm S} = 1/T_{\rm S}$ of the signal $s(t)$.
- The maximum delay time $\tau_\text{max} = M' \cdot \Delta \tau$ of this model is equal to the inverse of the coherence bandwidth $B_{\rm K}$. The number of paths considered is thus $M' = B_{\rm S}/B_{\rm K}$.
Here, too, usually no more than $M = 5$ main paths simultaneously provide a relevant contribution to the impulse response.
- The advantage over the first model is that for the delays now all values $\tau_m \le \tau_\text{max}$ are possible, with a temporal resolution of $\Delta \tau$ .
- At the end of next chapter The GWSSUS channel model we will come back to this general model again.
Exercises to chapter
Exercise 2.2: Simple Two-Path Channel Model
Exercise 2.2Z: Real Two-Path Channel
Exercise 2.3: Yet Another Multi-Path Channel
Exercise 2.4: 2-D Transfer Function