Aufgaben:Exercise 1.1: Music Signals: Difference between revisions
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Revision as of 16:11, 15 December 2020

noisy and/or distorted?
On the right you see a ca. $\text{30 ms}$ long section of a music signal [math]\displaystyle{ q(t) }[/math]. It is the piece „For Elise” by Ludwig van Beethoven.
- Underneath are drawn two sink signals [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math], which were recorded after the transmission of the music signal [math]\displaystyle{ q(t) }[/math] over two different channels.
- The following controls allow you to listen to the first fourteen seconds of each of the three audio signals [math]\displaystyle{ q(t) }[/math], [math]\displaystyle{ v_1(t) }[/math] and [math]\displaystyle{ v_2(t) }[/math].
Originalsignal [math]\displaystyle{ q(t) }[/math]
Sinkensignal [math]\displaystyle{ v_1(t) }[/math]
Sinkensignal [math]\displaystyle{ v_2(t) }[/math]
Notes:
- The task belongs to chapter Prinzip der Nachrichtenübertragung.
Questions
Solution
(1) Correct is the solution 2:
- In the marked range of $20$ milliseconds approx. $10$ oscillations can be detected.
- From this the result follows approximately for the signal frequency; $f = {10}/(20 \,\text{ms}) = 500 \,\text{Hz}$.
(2) Correct is the solution 1:
- The signal [math]\displaystyle{ v_1(t) }[/math] is undistorted compared to the original signal [math]\displaystyle{ q(t) }[/math]. The following applies: $v_1(t)=\alpha \cdot q(t-\tau) .$
- An attenuation [math]\displaystyle{ \alpha }[/math] and a delay [math]\displaystyle{ \tau }[/math] do not cause distortion, but the signal is then only quieter and comes later than the original.
(3) Correct are the solutions 1 and 3:
- One can recognize both in the displayed signal [math]\displaystyle{ v_2(t) }[/math] and in the audio signal additive noise ⇒ solution 3.
- The signal-to-noise ratio is approx. $\text{30 dB}$; but this cannot be seen from this representation.
- Correct is also the solution 1: Without this noise component [math]\displaystyle{ v_2(t) }[/math] identical with [math]\displaystyle{ q(t) }[/math].
(4) The signal [math]\displaystyle{ v_1(t) }[/math] is identical in form to the original signal [math]\displaystyle{ q(t) }[/math] and differs from it only
- by the attenuation factor $\alpha = \underline{\text{0.3}}$ (dies entspricht etwa $\text{–10 dB)}$
- and the delay $\tau = \underline{10\,\text{ms}}$.