Aufgaben:Exercise 1.1: Music Signals: Difference between revisions

From LNTwww
No edit summary
No edit summary
Line 51: Line 51:
+ The signal&nbsp; <math>v_2(t)</math>&nbsp; is noisy compared to&nbsp; <math>q(t)</math>&nbsp;.
+ The signal&nbsp; <math>v_2(t)</math>&nbsp; is noisy compared to&nbsp; <math>q(t)</math>&nbsp;.


{One of the signals is undistorted and not noisy compared to the original &nbsp; <math>q(t)</math>&nbsp;. <br> Estimate the attenuation factor and the running time for this.
{One of the signals is undistorted and not noisy compared to the original &nbsp; <math>q(t)</math>&nbsp;. <br> Estimate the attenuation factor and the delay time for this.
|type="{}"}
|type="{}"}
<math> \alpha \ = \ </math> { 0.2-0.4 }
<math> \alpha \ = \ </math> { 0.2-0.4 }
Line 62: Line 62:
{{ML-Kopf}}
{{ML-Kopf}}
'''(1)'''&nbsp;  Correct is the <u>solution 2</u>:
'''(1)'''&nbsp;  Correct is the <u>solution 2</u>:
*In the marked range of $20$ milliseconds approx. &nbsp; $10$&nbsp; oscillations can be detected.  
*In the marked range of&nbsp; $20$&nbsp; milliseconds approx.&nbsp; $10$&nbsp; oscillations can be detected.  
*From this the result&nbsp; follows approximately for the signal frequency; $f = {10}/(20 \,\text{ms}) =  500 \,\text{Hz}$.
*From this the result&nbsp; follows approximately for the signal frequency&nbsp; $f = {10}/(20 \,\text{ms}) =  500 \,\text{Hz}$.






'''(2)'''&nbsp; Correct is the <u>solution 1</u>:
'''(2)'''&nbsp; Correct is the <u>solution 1</u>:
*The signal&nbsp; <math>v_1(t)</math>&nbsp; is undistorted compared to the original signal <math>q(t)</math>. The following applies: &nbsp; $v_1(t)=\alpha \cdot q(t-\tau) .$
*The signal&nbsp; <math>v_1(t)</math>&nbsp; is undistorted compared to the original signal <math>q(t)</math>.&nbsp; The following applies: &nbsp; $v_1(t)=\alpha \cdot q(t-\tau)$.


*An attenuation&nbsp; <math>\alpha</math>&nbsp; and a delay&nbsp; <math>\tau</math>&nbsp; do not cause distortion, but the signal is then only quieter and delayed in time, compared to the original.
*An attenuation&nbsp; <math>\alpha</math>&nbsp; and a delay&nbsp; <math>\tau</math>&nbsp; do not cause distortion, but the signal is then only quieter and delayed in time, compared to the original.
Line 75: Line 75:


'''(3)'''&nbsp; Correct are the <u>solutions 1 and 3</u>:
'''(3)'''&nbsp; Correct are the <u>solutions 1 and 3</u>:
*One can recognize both in the displayed signal&nbsp; <math>v_2(t)</math>&nbsp; and in the audio signal&nbsp; ''additive noise'' &nbsp; ⇒ &nbsp; <u>solution 3</u>.  
*One can recognize additive noise both in the displayed signal&nbsp; <math>v_2(t)</math>&nbsp; and in the audio signal&nbsp; &nbsp; ⇒ &nbsp; <u>solution 3</u>.  
*The signal-to-noise ratio is approx. &nbsp; $\text{30 dB}$; but this cannot be seen from this representation.  
*The signal-to-noise ratio is approx.&nbsp; $\text{30 dB}$;&nbsp; but this cannot be seen from this representation.  
*Correct is also the <u>solution 1</u>: &nbsp; Without this noise component&nbsp; <math>v_2(t)</math>&nbsp; identical with&nbsp; <math>q(t)</math>.
*Correct is also the <u>solution 1</u>: &nbsp; Without this noise component&nbsp; <math>v_2(t)</math>&nbsp; would be identical with&nbsp; <math>q(t)</math>.




'''(4)'''&nbsp;  The signal&nbsp; <math>v_1(t)</math>&nbsp; is identical in form to the original signal&nbsp; <math>q(t)</math>&nbsp; and differs from it only  
'''(4)'''&nbsp;  The signal&nbsp; <math>v_1(t)</math>&nbsp; is identical in form to the original signal&nbsp; <math>q(t)</math>&nbsp; and differs from it only  
*by the attenuation factor&nbsp; $\alpha = \underline{\text{0.3}}$&nbsp;  (dies entspricht etwa&nbsp; $\text{–10 dB)}$  
*by the attenuation factor&nbsp; $\alpha = \underline{\text{0.3}}$ &nbsp;  $($this corresponds to about&nbsp; $\text{–10 dB)}$  
*and the delay&nbsp;  $\tau = \underline{10\,\text{ms}}$.
*and the delay&nbsp;  $\tau = \underline{10\,\text{ms}}$.
{{ML-Fuß}}
{{ML-Fuß}}

Revision as of 10:32, 8 April 2021

Music signals, original,
noisy and/or distorted?

On the right you see a  $\text{30 ms}$  long section of a music signal  [math]\displaystyle{ q(t) }[/math].  It is the piece  "For Elise"  by Ludwig van Beethoven.

  • Underneath are drawn two sink signals  [math]\displaystyle{ v_1(t) }[/math]  and  [math]\displaystyle{ v_2(t) }[/math], which were recorded after the transmission of the music signal  [math]\displaystyle{ q(t) }[/math]  over two different channels.
  • The following operating elements allow you to listen to the first fourteen seconds of each of the three audio signals  [math]\displaystyle{ q(t) }[/math][math]\displaystyle{ v_1(t) }[/math]  and  [math]\displaystyle{ v_2(t) }[/math].


Original signal  [math]\displaystyle{ q(t) }[/math]:

Sink signal  [math]\displaystyle{ v_1(t) }[/math]:

Sink signal  [math]\displaystyle{ v_2(t) }[/math]:



Notes:



Questions

1 Estimate the signal frequency of  [math]\displaystyle{ q(t) }[/math]  in the displayed section.

The signal frequency is approximately  [math]\displaystyle{ f = 250\,\text{Hz} }[/math].
The signal frequency is approximately  [math]\displaystyle{ f = 500\,\text{Hz} }[/math].
The signal frequency is about  [math]\displaystyle{ f = 1\,\text{kHz} }[/math].

2 Which statements are true for the signal  [math]\displaystyle{ v_1(t) }[/math] ?

The signal  [math]\displaystyle{ v_1(t) }[/math]  is undistorted compared to  [math]\displaystyle{ q(t) }[/math].
The signal  [math]\displaystyle{ v_1(t) }[/math]  shows distortions compared to  [math]\displaystyle{ q(t) }[/math] .
The signal  [math]\displaystyle{ v_1(t) }[/math]  is noisy compared to  [math]\displaystyle{ q(t) }[/math] .

3 Which statements are true for the signal  [math]\displaystyle{ v_2(t) }[/math] ?

The signal  [math]\displaystyle{ v_2(t) }[/math]  is undistorted compared to  [math]\displaystyle{ q(t) }[/math] .
The signal  [math]\displaystyle{ v_2(t) }[/math]  shows distortions compared to  [math]\displaystyle{ q(t) }[/math] .
The signal  [math]\displaystyle{ v_2(t) }[/math]  is noisy compared to  [math]\displaystyle{ q(t) }[/math] .

4 One of the signals is undistorted and not noisy compared to the original   [math]\displaystyle{ q(t) }[/math] .
Estimate the attenuation factor and the delay time for this.

[math]\displaystyle{ \alpha \ = \ }[/math]
[math]\displaystyle{ \tau \ = \ }[/math] $\ \text{ms}$


Solution

(1)  Correct is the solution 2:

  • In the marked range of  $20$  milliseconds approx.  $10$  oscillations can be detected.
  • From this the result  follows approximately for the signal frequency  $f = {10}/(20 \,\text{ms}) = 500 \,\text{Hz}$.


(2)  Correct is the solution 1:

  • The signal  [math]\displaystyle{ v_1(t) }[/math]  is undistorted compared to the original signal [math]\displaystyle{ q(t) }[/math].  The following applies:   $v_1(t)=\alpha \cdot q(t-\tau)$.
  • An attenuation  [math]\displaystyle{ \alpha }[/math]  and a delay  [math]\displaystyle{ \tau }[/math]  do not cause distortion, but the signal is then only quieter and delayed in time, compared to the original.


(3)  Correct are the solutions 1 and 3:

  • One can recognize additive noise both in the displayed signal  [math]\displaystyle{ v_2(t) }[/math]  and in the audio signal    ⇒   solution 3.
  • The signal-to-noise ratio is approx.  $\text{30 dB}$;  but this cannot be seen from this representation.
  • Correct is also the solution 1:   Without this noise component  [math]\displaystyle{ v_2(t) }[/math]  would be identical with  [math]\displaystyle{ q(t) }[/math].


(4)  The signal  [math]\displaystyle{ v_1(t) }[/math]  is identical in form to the original signal  [math]\displaystyle{ q(t) }[/math]  and differs from it only

  • by the attenuation factor  $\alpha = \underline{\text{0.3}}$   $($this corresponds to about  $\text{–10 dB)}$
  • and the delay  $\tau = \underline{10\,\text{ms}}$.