Aufgaben:Exercise 4.08Z: Basics about Interleaving: Difference between revisions

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{{quiz-Header|Buchseite=Kanalcodierung/Grundlegendes zu den Turbocodes}}
{{quiz-Header|Buchseite=Kanalcodierung/Grundlegendes zu den Turbocodes}}


[[File:P_ID3032__KC_Z_4_8_v3.png|right|frame|Interleaver–Beschreibung für drei Beispiele]]
[[File:P_ID3032__KC_Z_4_8_v3.png|right|frame|Interleaver description]]
Interleaving is required,   for example,   for a channel with burst error characteristics in order to distribute the errors within the burst over a sufficiently large area so that they can subsequently be largely corrected   $($or at least detected$)$.


For turbo codes based on so-called  '''RSC encoder'''  $($"Recursive Systematic Convolutional Encoder"$)$  – and only such make sense – interleaving is essential also with the AWGN channel,  because then there are also always $($some$)$ input sequences,  which deliver only  "zeros"  in the output sequence after quite a few  "ones",  and that to infinity   ⇒   there are output sequences with very small Hamming weight.


If the bits of such input sequences are distributed over a wide range in the second encoder,  the problem can be largely eliminated by the interaction of both component decoders in the case of iterative symbol-wise decoding.


===Fragebogen===
A general distinction is made between
* '''block interleaver''' and
 
* '''random interleaver'''.
 
 
In block interleaving  one fills a matrix with  $N_{\rm C}$  columns and  $N_{\rm R}$  rows column-by-column and reads the matrix row-by-row.  This deterministically scrambles a block of information with  $I_{\rm max} = N_{\rm C} \cdot N_{\rm R}$  bits.
 
On the right,  two interleavers are indicated and in graphical form by the assignment  $I_{\rm Out}(I_{\rm In})$.  These quantities represent the  "output sequence index"  and the  "input sequence index",  respectively.  It holds:
:$$1 \le I_{\rm Out} \le I_{\rm max} \hspace{0.05cm},$$
:$$1 \le I_{\rm In} \le I_{\rm max} \hspace{0.05cm}. $$
 
In the subtask  '''(1)'''  it is asked whether this is  "block interleaving"  or  "random interleaving".  The latter are discussed in the  [[Channel_Coding/The_Basics_of_Turbo_Codes#Second_requirement_for_turbo_codes:_Interleaving|"theory section"]]  but only very briefly.
 
 
 
 
 
<u>Hints:</u>
* The exercise refers to the chapter&nbsp; [[Channel_Coding/The_Basics_of_Turbo_Codes| "Basics of Turbo Codes"]].
 
*But other&nbsp; $\rm LNTwww$&nbsp; books also discuss interleaving,&nbsp; including the book&nbsp; "Examples of Communication Systems"&nbsp; with reference to the
:* standard digital subscriber line</i> $\rm (DSL)$ &nbsp; &#8658; &nbsp; [[Examples_of_Communication_Systems/Methods_to_Reduce_the_Bit_Error_Rate_in_DSL#Interleaving_und_De.E2.80.93Interleaving| "Interleaving and Deinterleaving"]],
:* 2G mobile communication system&nbsp; $\rm GSM$ &nbsp; &#8658; &nbsp; [[Examples_of_Communication_Systems/Entire_GSM_Transmission_System#Komponenten_der_Sprach.E2.80.93_und_Daten.C3.BCbertragung| "Components of voice and data transmission"]],
:* 3G mobile communication system&nbsp; $\rm UMTS$ &nbsp; &#8658; &nbsp; [[Examples_of_Communication_Systems/Telecommunications_Aspects_of_UMTS#Kanalcodierung_bei_UMTS| "Channel Coding"]],
:* 4G mobile communication system&nbsp; $\rm LTE$ &nbsp; &#8658; &nbsp; [[Mobile_Communications/The_Application_of_OFDMA_and_SC-FDMA_in_LTE#Functionality_of_SC-FDMA| "Functionality of SC-FDMA"]]&nbsp; $($in the boo&nbsp; "Mobile Communications"$)$.
 
 
 
 
===Questions===
<quiz display=simple>
<quiz display=simple>
{Multiple-Choice
{What interleaver type is shown in the graphic on the details page?
|type="[]"}
|type="()"}
+ correct
+ Block interleaving,
- false
- Random interleaving.


{Input-Box Frage
{How many rows&nbsp; ($N_{\rm R}$)&nbsp; and columns&nbsp; ($N_{\rm C}$)&nbsp; does the upper "Interleaver matrix 1" have?
|type="{}"}
|type="{}"}
$xyz \ = \ ${ 5.4 3% } $ab$
$N_{\rm R} \ = \ ${ 4 }
$N_{\rm C} \ = \ ${ 3 }  
 
{It holds &nbsp; $\underline{u} = (1001'0001'1101'1101'0010'0111)$.&nbsp; How does the scrambled sequence&nbsp; $\underline{u}_{\pi}$ begin?&nbsp; &nbsp; Note: &nbsp; The quotation marks serve only as a reading aid.
|type="()"}
- $\underline{u}_{\pi} = (110'100'100'011'111'110'010'001' \text{...}\ )$,
+ $\underline{u}_{\pi} = (101'001'000'111'100'101'011'101'\text{...}\ )$.
 
{The scrambled sequence be&nbsp; $\underline{u}_{\pi} = (100'100'011'101'110'100'100'111)$.&nbsp; What is the sequence after de-interleaving?
|type="()"}
+ $\underline{u} = (1101'0010'0011'1111'1001'0001'\text{...}\ )$,
- $\underline{u} = (1010'0100'0111'1001'0101'1101' \text{...}\ )$.
</quiz>
</quiz>


===Musterlösung===
===Solution===
{{ML-Kopf}}
{{ML-Kopf}}
'''(1)'''&nbsp;  
[[File:P_ID3041__KC_Z_4_8b_v2.png|right|frame|$4×3$&nbsp; interleaver matrix]]
'''(2)'''&nbsp;  
'''(1)'''&nbsp; From the regular structure of the function&nbsp; $I_{\rm Out}(I_{\rm In})$&nbsp; one can see that it is a block interleaver &nbsp; &#8658; &nbsp; <u>Response 1</u>.
'''(3)'''&nbsp;  
 
'''(4)'''&nbsp;  
 
'''(5)'''&nbsp;  
'''(2)'''&nbsp; The index&nbsp; "1"&nbsp; is output as the first character.&nbsp; Further applies:
* The index 5 is output as the second character &nbsp; &#8658; &nbsp; $\underline{N_{\rm R} = 4}$.
 
* The index 2 is output as the fourth character &nbsp; &#8658; &nbsp; $\underline{N_{\rm C} = 3}$.
 
 
The upper graph shows for the&nbsp; $4×3$&nbsp; interleaver matrix:
* the column-by-column write&nbsp; $($red$)$,
* the row-by-row readout&nbsp; $($green$)$.
 
 
 
[[File:P_ID3042__KC_Z_4_8c_v3.png|right|frame|Interleaving]]
'''(3)'''&nbsp; Correct is&nbsp; <u>the proposed solution 2</u>:
*The matrix is written column-by-column and read row-by-row.
*After&nbsp; $12$&nbsp; bits,&nbsp; the matrix is cleared and the procedure starts again.
 
*The graphic shows that the solution suggestion 2  is correct.
<br clear=all>
[[File:P_ID3043__KC_Z_4_8d_v1.png|right|frame|De–interleaving]]
'''(4)'''&nbsp; Correct is&nbsp; <u>the proposed solution 1</u>:
*In de-interleaving,&nbsp; the matrix is written row-by-row and read column-by-column.
*The graphic shows that here the solution suggestion 1 is correct.
 
 
{{ML-Fuß}}
{{ML-Fuß}}






[[Category:Aufgaben zu  Kanalcodierung|^4.3 Grundlegendes zu den Turbocodes^]]
[[Category:Channel Coding: Exercises|^4.3 About the Turbo Codes^]]
[[de:Aufgaben:Aufgabe 4.08Z: Grundlegendes zum Interleaving]]

Latest revision as of 17:55, 16 March 2026

Interleaver description

Interleaving is required,  for example,  for a channel with burst error characteristics in order to distribute the errors within the burst over a sufficiently large area so that they can subsequently be largely corrected  $($or at least detected$)$.

For turbo codes based on so-called  RSC encoder  $($"Recursive Systematic Convolutional Encoder"$)$  – and only such make sense – interleaving is essential also with the AWGN channel,  because then there are also always $($some$)$ input sequences,  which deliver only  "zeros"  in the output sequence after quite a few  "ones",  and that to infinity   ⇒   there are output sequences with very small Hamming weight.

If the bits of such input sequences are distributed over a wide range in the second encoder,  the problem can be largely eliminated by the interaction of both component decoders in the case of iterative symbol-wise decoding.

A general distinction is made between

  • block interleaver and
  • random interleaver.


In block interleaving  one fills a matrix with  $N_{\rm C}$  columns and  $N_{\rm R}$  rows column-by-column and reads the matrix row-by-row.  This deterministically scrambles a block of information with  $I_{\rm max} = N_{\rm C} \cdot N_{\rm R}$  bits.

On the right,  two interleavers are indicated and in graphical form by the assignment  $I_{\rm Out}(I_{\rm In})$.  These quantities represent the  "output sequence index"  and the  "input sequence index",  respectively.  It holds:

$$1 \le I_{\rm Out} \le I_{\rm max} \hspace{0.05cm},$$
$$1 \le I_{\rm In} \le I_{\rm max} \hspace{0.05cm}. $$

In the subtask  (1)  it is asked whether this is  "block interleaving"  or  "random interleaving".  The latter are discussed in the  "theory section"  but only very briefly.



Hints:

  • But other  $\rm LNTwww$  books also discuss interleaving,  including the book  "Examples of Communication Systems"  with reference to the



Questions

1 What interleaver type is shown in the graphic on the details page?

Block interleaving,
Random interleaving.

2 How many rows  ($N_{\rm R}$)  and columns  ($N_{\rm C}$)  does the upper "Interleaver matrix 1" have?

$N_{\rm R} \ = \ $
$N_{\rm C} \ = \ $

3 It holds   $\underline{u} = (1001'0001'1101'1101'0010'0111)$.  How does the scrambled sequence  $\underline{u}_{\pi}$ begin?    Note:   The quotation marks serve only as a reading aid.

$\underline{u}_{\pi} = (110'100'100'011'111'110'010'001' \text{...}\ )$,
$\underline{u}_{\pi} = (101'001'000'111'100'101'011'101'\text{...}\ )$.

4 The scrambled sequence be  $\underline{u}_{\pi} = (100'100'011'101'110'100'100'111)$.  What is the sequence after de-interleaving?

$\underline{u} = (1101'0010'0011'1111'1001'0001'\text{...}\ )$,
$\underline{u} = (1010'0100'0111'1001'0101'1101' \text{...}\ )$.


Solution

$4×3$  interleaver matrix

(1)  From the regular structure of the function  $I_{\rm Out}(I_{\rm In})$  one can see that it is a block interleaver   ⇒   Response 1.


(2)  The index  "1"  is output as the first character.  Further applies:

  • The index 5 is output as the second character   ⇒   $\underline{N_{\rm R} = 4}$.
  • The index 2 is output as the fourth character   ⇒   $\underline{N_{\rm C} = 3}$.


The upper graph shows for the  $4×3$  interleaver matrix:

  • the column-by-column write  $($red$)$,
  • the row-by-row readout  $($green$)$.


Interleaving

(3)  Correct is  the proposed solution 2:

  • The matrix is written column-by-column and read row-by-row.
  • After  $12$  bits,  the matrix is cleared and the procedure starts again.
  • The graphic shows that the solution suggestion 2 is correct.


De–interleaving

(4)  Correct is  the proposed solution 1:

  • In de-interleaving,  the matrix is written row-by-row and read column-by-column.
  • The graphic shows that here the solution suggestion 1 is correct.