Difference between revisions of "Aufgaben:Exercise 4.08Z: Basics about Interleaving"
m (Text replacement - "Category:Aufgaben zu Kanalcodierung" to "Category:Channel Coding: Exercises") |
|||
(10 intermediate revisions by 3 users not shown) | |||
Line 1: | Line 1: | ||
{{quiz-Header|Buchseite=Kanalcodierung/Grundlegendes zu den Turbocodes}} | {{quiz-Header|Buchseite=Kanalcodierung/Grundlegendes zu den Turbocodes}} | ||
− | [[File:P_ID3032__KC_Z_4_8_v3.png|right|frame| | + | [[File:P_ID3032__KC_Z_4_8_v3.png|right|frame|Interleaver description]] |
− | Interleaving | + | Interleaving is required, for example, for a channel with burst error characteristics in order to distribute the errors within the burst over a sufficiently large area so that they can subsequently be largely corrected $($or at least detected$)$. |
− | + | For turbo codes based on so-called '''RSC encoder''' $($"Recursive Systematic Convolutional Encoder"$)$ – and only such make sense – interleaving is essential also with the AWGN channel, because then there are also always $($some$)$ input sequences, which deliver only "zeros" in the output sequence after quite a few "ones", and that to infinity ⇒ there are output sequences with very small Hamming weight. | |
− | + | If the bits of such input sequences are distributed over a wide range in the second encoder, the problem can be largely eliminated by the interaction of both component decoders in the case of iterative symbol-wise decoding. | |
− | + | A general distinction is made between | |
− | * ''' | + | * '''block interleaver''' and |
− | |||
+ | * '''random interleaver'''. | ||
− | |||
− | + | In block interleaving one fills a matrix with $N_{\rm C}$ columns and $N_{\rm R}$ rows column-by-column and reads the matrix row-by-row. This deterministically scrambles a block of information with $I_{\rm max} = N_{\rm C} \cdot N_{\rm R}$ bits. | |
− | |||
− | |||
− | + | On the right, two interleavers are indicated and in graphical form by the assignment $I_{\rm Out}(I_{\rm In})$. These quantities represent the "output sequence index" and the "input sequence index", respectively. It holds: | |
+ | :$$1 \le I_{\rm Out} \le I_{\rm max} \hspace{0.05cm},$$ | ||
+ | :$$1 \le I_{\rm In} \le I_{\rm max} \hspace{0.05cm}. $$ | ||
+ | In the subtask '''(1)''' it is asked whether this is "block interleaving" or "random interleaving". The latter are discussed in the [[Channel_Coding/The_Basics_of_Turbo_Codes#Second_requirement_for_turbo_codes:_Interleaving|"theory section"]] but only very briefly. | ||
− | |||
− | |||
− | + | <u>Hints:</u> | |
− | + | * The exercise refers to the chapter [[Channel_Coding/The_Basics_of_Turbo_Codes| "Basics of Turbo Codes"]]. | |
− | |||
− | |||
− | |||
+ | *But other $\rm LNTwww$ books also discuss interleaving, including the book "Examples of Communication Systems" with reference to the | ||
+ | :* standard digital subscriber line</i> $\rm (DSL)$ ⇒ [[Examples_of_Communication_Systems/Methods_to_Reduce_the_Bit_Error_Rate_in_DSL#Interleaving_und_De.E2.80.93Interleaving| "Interleaving and Deinterleaving"]], | ||
+ | :* 2G mobile communication system $\rm GSM$ ⇒ [[Examples_of_Communication_Systems/Entire_GSM_Transmission_System#Komponenten_der_Sprach.E2.80.93_und_Daten.C3.BCbertragung| "Components of voice and data transmission"]], | ||
+ | :* 3G mobile communication system $\rm UMTS$ ⇒ [[Examples_of_Communication_Systems/Telecommunications_Aspects_of_UMTS#Kanalcodierung_bei_UMTS| "Channel Coding"]], | ||
+ | :* 4G mobile communication system $\rm LTE$ ⇒ [[Mobile_Communications/The_Application_of_OFDMA_and_SC-FDMA_in_LTE#Functionality_of_SC-FDMA| "Functionality of SC-FDMA"]] $($in the boo "Mobile Communications"$)$. | ||
− | === | + | |
+ | ===Questions=== | ||
<quiz display=simple> | <quiz display=simple> | ||
− | { | + | {What interleaver type is shown in the graphic on the details page? |
|type="()"} | |type="()"} | ||
− | + Block | + | + Block interleaving, |
− | - Random | + | - Random interleaving. |
− | { | + | {How many rows ($N_{\rm R}$) and columns ($N_{\rm C}$) does the upper "Interleaver matrix 1" have? |
|type="{}"} | |type="{}"} | ||
− | $ | + | $N_{\rm R} \ = \ ${ 4 } |
− | $ | + | $N_{\rm C} \ = \ ${ 3 } |
− | { | + | {It holds $\underline{u} = (1001'0001'1101'1101'0010'0111)$. How does the scrambled sequence $\underline{u}_{\pi}$ begin? Note: The quotation marks serve only as a reading aid. |
|type="()"} | |type="()"} | ||
- $\underline{u}_{\pi} = (110'100'100'011'111'110'010'001' \text{...}\ )$, | - $\underline{u}_{\pi} = (110'100'100'011'111'110'010'001' \text{...}\ )$, | ||
+ $\underline{u}_{\pi} = (101'001'000'111'100'101'011'101'\text{...}\ )$. | + $\underline{u}_{\pi} = (101'001'000'111'100'101'011'101'\text{...}\ )$. | ||
− | { | + | {The scrambled sequence be $\underline{u}_{\pi} = (100'100'011'101'110'100'100'111)$. What is the sequence after de-interleaving? |
|type="()"} | |type="()"} | ||
+ $\underline{u} = (1101'0010'0011'1111'1001'0001'\text{...}\ )$, | + $\underline{u} = (1101'0010'0011'1111'1001'0001'\text{...}\ )$, | ||
Line 60: | Line 61: | ||
</quiz> | </quiz> | ||
− | === | + | ===Solution=== |
{{ML-Kopf}} | {{ML-Kopf}} | ||
− | [[File:P_ID3041__KC_Z_4_8b_v2.png|right|frame| | + | [[File:P_ID3041__KC_Z_4_8b_v2.png|right|frame|$4×3$ interleaver matrix]] |
− | '''(1)''' | + | '''(1)''' From the regular structure of the function $I_{\rm Out}(I_{\rm In})$ one can see that it is a block interleaver ⇒ <u>Response 1</u>. |
+ | |||
+ | |||
+ | '''(2)''' The index "1" is output as the first character. Further applies: | ||
+ | * The index 5 is output as the second character ⇒ $\underline{N_{\rm R} = 4}$. | ||
+ | * The index 2 is output as the fourth character ⇒ $\underline{N_{\rm C} = 3}$. | ||
− | |||
− | |||
− | |||
+ | The upper graph shows for the $4×3$ interleaver matrix: | ||
+ | * the column-by-column write $($red$)$, | ||
+ | |||
+ | * the row-by-row readout $($green$)$. | ||
− | |||
− | |||
− | |||
+ | [[File:P_ID3042__KC_Z_4_8c_v3.png|right|frame|Interleaving]] | ||
+ | '''(3)''' Correct is <u>the proposed solution 2</u>: | ||
+ | *The matrix is written column-by-column and read row-by-row. | ||
+ | |||
+ | *After $12$ bits, the matrix is cleared and the procedure starts again. | ||
− | + | *The graphic shows that the solution suggestion 2 is correct. | |
− | |||
− | |||
− | |||
− | * | ||
<br clear=all> | <br clear=all> | ||
− | [[File:P_ID3043__KC_Z_4_8d_v1.png|right|frame| | + | [[File:P_ID3043__KC_Z_4_8d_v1.png|right|frame|De–interleaving]] |
− | '''(4)''' | + | '''(4)''' Correct is <u>the proposed solution 1</u>: |
− | * | + | *In de-interleaving, the matrix is written row-by-row and read column-by-column. |
− | * | + | |
+ | *The graphic shows that here the solution suggestion 1 is correct. | ||
Line 93: | Line 99: | ||
− | [[Category:Channel Coding: Exercises|^4.3 | + | [[Category:Channel Coding: Exercises|^4.3 About the Turbo Codes^]] |
Latest revision as of 13:53, 14 December 2022
Interleaving is required, for example, for a channel with burst error characteristics in order to distribute the errors within the burst over a sufficiently large area so that they can subsequently be largely corrected $($or at least detected$)$.
For turbo codes based on so-called RSC encoder $($"Recursive Systematic Convolutional Encoder"$)$ – and only such make sense – interleaving is essential also with the AWGN channel, because then there are also always $($some$)$ input sequences, which deliver only "zeros" in the output sequence after quite a few "ones", and that to infinity ⇒ there are output sequences with very small Hamming weight.
If the bits of such input sequences are distributed over a wide range in the second encoder, the problem can be largely eliminated by the interaction of both component decoders in the case of iterative symbol-wise decoding.
A general distinction is made between
- block interleaver and
- random interleaver.
In block interleaving one fills a matrix with $N_{\rm C}$ columns and $N_{\rm R}$ rows column-by-column and reads the matrix row-by-row. This deterministically scrambles a block of information with $I_{\rm max} = N_{\rm C} \cdot N_{\rm R}$ bits.
On the right, two interleavers are indicated and in graphical form by the assignment $I_{\rm Out}(I_{\rm In})$. These quantities represent the "output sequence index" and the "input sequence index", respectively. It holds:
- $$1 \le I_{\rm Out} \le I_{\rm max} \hspace{0.05cm},$$
- $$1 \le I_{\rm In} \le I_{\rm max} \hspace{0.05cm}. $$
In the subtask (1) it is asked whether this is "block interleaving" or "random interleaving". The latter are discussed in the "theory section" but only very briefly.
Hints:
- The exercise refers to the chapter "Basics of Turbo Codes".
- But other $\rm LNTwww$ books also discuss interleaving, including the book "Examples of Communication Systems" with reference to the
- standard digital subscriber line $\rm (DSL)$ ⇒ "Interleaving and Deinterleaving",
- 2G mobile communication system $\rm GSM$ ⇒ "Components of voice and data transmission",
- 3G mobile communication system $\rm UMTS$ ⇒ "Channel Coding",
- 4G mobile communication system $\rm LTE$ ⇒ "Functionality of SC-FDMA" $($in the boo "Mobile Communications"$)$.
Questions
Solution
(1) From the regular structure of the function $I_{\rm Out}(I_{\rm In})$ one can see that it is a block interleaver ⇒ Response 1.
(2) The index "1" is output as the first character. Further applies:
- The index 5 is output as the second character ⇒ $\underline{N_{\rm R} = 4}$.
- The index 2 is output as the fourth character ⇒ $\underline{N_{\rm C} = 3}$.
The upper graph shows for the $4×3$ interleaver matrix:
- the column-by-column write $($red$)$,
- the row-by-row readout $($green$)$.
(3) Correct is the proposed solution 2:
- The matrix is written column-by-column and read row-by-row.
- After $12$ bits, the matrix is cleared and the procedure starts again.
- The graphic shows that the solution suggestion 2 is correct.
(4) Correct is the proposed solution 1:
- In de-interleaving, the matrix is written row-by-row and read column-by-column.
- The graphic shows that here the solution suggestion 1 is correct.